Timeline for Two charged capacitors connected in series
Current License: CC BY-SA 4.0
10 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jul 17, 2020 at 12:07 | vote | accept | Adithya | ||
| Jul 16, 2020 at 17:58 | vote | accept | Adithya | ||
| Jul 17, 2020 at 12:06 | |||||
| Mar 30, 2020 at 15:44 | comment | added | user136077 | Some care is needed. Initial conditions affect the result, because both of the caps get exactly the same amount of charging or discharging. | |
| Mar 30, 2020 at 14:54 | answer | added | WindSoul | timeline score: 3 | |
| Mar 30, 2020 at 14:27 | answer | added | user136077 | timeline score: 2 | |
| Mar 30, 2020 at 13:28 | answer | added | across | timeline score: 1 | |
| Mar 30, 2020 at 13:00 | comment | added | across | Some song and dance happens initially, but the transient passes and it will reach a steadystate value. This final value is a simple series capacitance calculation. It settles to 1/11*V1 no matter the initial conditions. | |
| Mar 30, 2020 at 12:45 | comment | added | Adithya | If both the capacitors are holding charge and I connect them back to back (series) with the supply and ground , shouldn't there be some type of charge rearrangement causing Vfinal to settle to some value? IMO it is not a simple Series capacitance calculation then. | |
| Mar 30, 2020 at 11:48 | comment | added | across | Hint: Initial condition doesn't matter for Vfinal | |
| Mar 30, 2020 at 11:46 | history | asked | Adithya | CC BY-SA 4.0 |