Timeline for How to model and understand the asymmetry of a parallel RLC circuit spectrum
Current License: CC BY-SA 4.0
17 events
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| May 2, 2020 at 15:02 | history | edited | user27119 | CC BY-SA 4.0 |
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| May 2, 2020 at 14:46 | history | edited | user27119 | CC BY-SA 4.0 |
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| May 2, 2020 at 11:48 | vote | accept | user27119 | ||
| May 2, 2020 at 11:34 | answer | added | Andy aka | timeline score: 1 | |
| May 2, 2020 at 11:20 | comment | added | Andy aka | So, the "real" (noise producing) resistor is in series with the inductor and not parallel to the inductor, yes? | |
| May 2, 2020 at 10:43 | comment | added | user27119 | Ahhhh, now I see. Unfortunately I can't. The RCL circuit is actually a shielded inductor, so a solenoid inside of a copper can essentially. The capacitance is parasitic coming from coil-to-coil and coil-to-shield interactions. The resistive component is emergent, so \$ R = \omega_{0} Q L\$ | |
| May 2, 2020 at 10:38 | comment | added | Andy aka | Exactly - remove L and C and plot the noise. | |
| May 2, 2020 at 10:37 | comment | added | skvery | @Q.P., Andyaka means that you can also include a graph with C and L disconnected. You must also include the source resistance of the noise source in your equivalent circuit. It might also be instructive to connect C and L separately and then show the spectrum. | |
| May 2, 2020 at 10:26 | comment | added | user27119 | The signal is simply the amplified Johnson-Nyquist noise of the circuit there is no external RF drive being applied. | |
| May 2, 2020 at 10:24 | history | edited | user27119 | CC BY-SA 4.0 |
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| May 2, 2020 at 10:22 | comment | added | Andy aka | The question has no foundations without the spectrum being flat and knowledge of how you apply the signal. Surely that must be obvious? | |
| May 2, 2020 at 10:20 | comment | added | Andy aka |
LATEX tip: \$ needs to be applied before and after formulae.
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| May 2, 2020 at 10:20 | comment | added | user27119 | How would one demonstrate that? I'm happy to add the circuit, but I'm not sure what that adds? It's a parallel RCL circuit, or are you interested in how the excitation is applied? | |
| May 2, 2020 at 10:16 | comment | added | Andy aka | Flat = equal power at all frequencies. Show your circuit too. | |
| May 2, 2020 at 10:16 | comment | added | user27119 | @Andyaka What do you mean by flat? | |
| May 2, 2020 at 10:15 | comment | added | Andy aka | You haven't demonstrated that your applied spectrum is flat. Neither have you shown how you apply the spectrum of noise to your filter. | |
| May 2, 2020 at 10:07 | history | asked | user27119 | CC BY-SA 4.0 |