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Jun 28, 2020 at 18:00 history tweeted twitter.com/StackElectronix/status/1277300757168099329
Jun 28, 2020 at 14:38 answer added Circuit fantasist timeline score: 3
Jun 28, 2020 at 12:28 comment added Horror Vacui You might check this answer: electronics.stackexchange.com/a/497821/152483 . Although it is about MOS transistor, the principle is the same: smaller sensitivity.
Jun 28, 2020 at 12:09 history became hot network question
Jun 28, 2020 at 11:12 answer added analogsystemsrf timeline score: 1
Jun 28, 2020 at 10:50 vote accept Kinka-Byo
Jun 28, 2020 at 9:21 answer added Daniele Tampieri timeline score: 6
Jun 28, 2020 at 7:56 comment added Andy aka (1) Most signal sources are voltage (2) converting a voltage source is complicated (3) running BJTs at maximum beta produces totally undesirable temperature/Beta problems (4) running with an emitter resistor solves this.
Jun 28, 2020 at 5:43 answer added Neil_UK timeline score: 4
Jun 28, 2020 at 4:28 comment added jonk Because \$\beta\$ isn't predictable. It varies from device to device within a family, varies over operating temperature, varies with respect to collector current (though more so at the extremes, I admit), drifts over time, etc. Better to operate it as an emitter follower (they call it emitter degeneration but it's really also just operating it as an emitter follower) that creates a nice, clean, predictable linear current vs input voltage.
Jun 28, 2020 at 4:22 comment added D.A.S. To resolve this issue, we add an emitter resistor to keep DC base current constant and then use the AC emitter voltage to modulate the AC current with less gain (=Rc/Re) but more linearity, or we use negative feedback which lowers impedance and less voltage gain (~70% Rf/Rin) but gives the best linearity.
Jun 28, 2020 at 4:06 history asked Kinka-Byo CC BY-SA 4.0