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AJN
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Image the address is 0x4000. Option (B) gives 0.1.(0+0)=0. The chip is selected even though the address is outside the range. You need to check not just if the options will give 0 for addresses in-range, but 1 for addresses outside the range.

Moreover, A12 is address line for the ROM so how can we use it for CS signal.

I don't understand fully, but aren't A15, A14, A13 also address lines for ROM? If theythe line coming out of the 8085 can be used why not A12 ?split into two traces, and connected to both the ROM and the CS generating circuit.

Image the address is 0x4000. Option (B) gives 0.1.(0+0)=0. The chip is selected even though the address is outside the range. You need to check not just if the options will give 0 for addresses in-range, but 1 for addresses outside the range.

Moreover, A12 is address line for the ROM so how can we use it for CS signal.

I don't understand fully, but aren't A15, A14, A13 also address lines for ROM? If they can be used why not A12 ?

Image the address is 0x4000. Option (B) gives 0.1.(0+0)=0. The chip is selected even though the address is outside the range. You need to check not just if the options will give 0 for addresses in-range, but 1 for addresses outside the range.

Moreover, A12 is address line for the ROM so how can we use it for CS signal.

I don't understand fully, but the line coming out of the 8085 can be split into two traces, and connected to both the ROM and the CS generating circuit.

Source Link
AJN
  • 3.9k
  • 1
  • 10
  • 20

Image the address is 0x4000. Option (B) gives 0.1.(0+0)=0. The chip is selected even though the address is outside the range. You need to check not just if the options will give 0 for addresses in-range, but 1 for addresses outside the range.

Moreover, A12 is address line for the ROM so how can we use it for CS signal.

I don't understand fully, but aren't A15, A14, A13 also address lines for ROM? If they can be used why not A12 ?