Timeline for Simplest Way to step down the 220AC with more than 10% efficiency
Current License: CC BY-SA 3.0
30 events
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Jun 11, 2020 at 15:10 | history | edited | CommunityBot |
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Aug 11, 2016 at 22:31 | comment | added | Gábor Móczik | Chip designing is totally out of my profession. 1V 10mA consumption equals to 10mW dissipation. If you make ANY type of regulator with 10% of effieciency you will end up at 90mW PSU + 10mW sensor dissipation. Isn't that too much? I mean, this will be a single-chip temperature sensor, won't that dissipation affect the measurement significantly? | |
Jan 10, 2013 at 17:32 | comment | added | placeholder | you should be made aware of this new answer to a similar sort of question here electronics.stackexchange.com/questions/53587/… | |
Jan 7, 2013 at 6:05 | vote | accept | alan | ||
Jan 7, 2013 at 6:05 | |||||
Jan 7, 2013 at 2:08 | answer | added | Olin Lathrop | timeline score: 1 | |
Jan 7, 2013 at 1:06 | comment | added | alan | @OlinLathrop I edit my question again, and thinks different methods for some time, hope you can check | |
Jan 6, 2013 at 16:52 | history | edited | alan | CC BY-SA 3.0 |
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Jan 4, 2013 at 12:18 | vote | accept | alan | ||
Jan 4, 2013 at 12:18 | |||||
Jan 4, 2013 at 10:10 | answer | added | Anindo Ghosh | timeline score: 3 | |
Jan 2, 2013 at 19:30 | review | Close votes | |||
Jan 4, 2013 at 19:53 | |||||
Jan 2, 2013 at 18:45 | answer | added | placeholder | timeline score: 5 | |
Jan 2, 2013 at 17:12 | comment | added | Olin Lathrop | Charge pumps can certainly step down as well as up. At high step down ratios, they look more like current sources. The current is a function of the capacitances and the pumping voltage and frequency. Capacitive charge pumps are common in un-isolated supplies that only need to put out a few mA. They are also fairly efficient. You would likely need to add some sort of regulation afterwards. This can be as simple as a zener shunt regulator since from 220V to 3V the charge pump will look like a current source. | |
Jan 2, 2013 at 15:33 | comment | added | Olin Lathrop | If the "connector" is just to plug into the wall outlet, then I don't see what the problem is. Use whatever the standard wall plug is for wherever this device will be used. As for 220 VAC on a chip, not gonna happen. The supply needs to be external to the chip, then whatever chips you have run from the resulting low voltage DC. A charge pump may be suitable, as I suggested to your original question days ago. | |
Jan 2, 2013 at 15:13 | history | edited | alan | CC BY-SA 3.0 |
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Jan 2, 2013 at 14:16 | comment | added | Olin Lathrop | We STILL don't know whether this power supply needs to be isolated. That must be decided first since the solutions either way will be very different. You say this will power a sensor, but where does the output of the sensor go? You also ask about a connector, so it implies the sensor signal may go elsewhere. If the sensor signal is just to be displayed locally, for example, then the supply could be isolated, but then the question about connector makes no sense. Also, what is this about, the electronics or the connector. Pick one. | |
Jan 2, 2013 at 14:09 | review | First posts | |||
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Jan 2, 2013 at 14:09 | history | reopened | W5VO | ||
Jan 2, 2013 at 13:14 | history | edited | alan | CC BY-SA 3.0 |
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Jan 2, 2013 at 13:02 | history | edited | alan | CC BY-SA 3.0 |
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S Dec 31, 2012 at 22:09 | history | suggested | DrFriedParts | CC BY-SA 3.0 |
Rewrite + personal letter in an attempt to salvage a potentially valuable future member
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Dec 31, 2012 at 21:37 | review | Suggested edits | |||
S Dec 31, 2012 at 22:09 | |||||
Dec 31, 2012 at 19:11 | history | closed |
Nick Alexeev Dave Tweed Leon Heller Olin Lathrop The Photon |
not a real question | |
Dec 31, 2012 at 13:22 | answer | added | Russell McMahon♦ | timeline score: 5 | |
Dec 31, 2012 at 11:09 | answer | added | user16324 | timeline score: 2 | |
Dec 31, 2012 at 4:43 | review | Close votes | |||
Dec 31, 2012 at 19:14 | |||||
Dec 31, 2012 at 4:39 | answer | added | placeholder | timeline score: 8 | |
Dec 31, 2012 at 4:07 | history | edited | alan | CC BY-SA 3.0 |
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Dec 31, 2012 at 3:02 | history | edited | alan | CC BY-SA 3.0 |
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Dec 31, 2012 at 2:46 | answer | added | DrFriedParts | timeline score: 6 | |
Dec 31, 2012 at 2:39 | history | asked | alan | CC BY-SA 3.0 |