Timeline for Why is there a low pass filter in a DSBSC demodulator?
Current License: CC BY-SA 4.0
28 events
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Oct 16, 2020 at 16:58 | vote | accept | Newton Nadar | ||
Oct 16, 2020 at 16:58 | comment | added | Newton Nadar | Thank you understood the problem with peak detector . | |
Oct 16, 2020 at 16:57 | vote | accept | Newton Nadar | ||
Oct 16, 2020 at 16:58 | |||||
Oct 15, 2020 at 20:26 | history | edited | JRE | CC BY-SA 4.0 |
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S Oct 15, 2020 at 17:27 | history | suggested | AJN | CC BY-SA 4.0 |
code formatting and spelling
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Oct 15, 2020 at 16:02 | answer | added | glen_geek | timeline score: 1 | |
Oct 15, 2020 at 16:00 | review | Suggested edits | |||
S Oct 15, 2020 at 17:27 | |||||
Oct 15, 2020 at 15:56 | comment | added | AJN | @NewtonNadar a peak detector would not work for suppressed carrier. During the negative cycles, the message is sitting in the valleys, not the peaks! Look carefully at the blue line in the third graph, particularly between 6 and 12 on the x axis. | |
Oct 15, 2020 at 15:54 | comment | added | Criticizing Israel not allowed | @NewtonNadar Would you say that tracking the peaks is... a type of low-pass filter? | |
Oct 15, 2020 at 15:51 | answer | added | AJN | timeline score: 1 | |
Oct 15, 2020 at 15:46 | comment | added | AJN |
@NewtonNadar Why does the code use sind instead of sin ? sind is very likely the wrong function to use in this context.
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Oct 15, 2020 at 15:45 | comment | added | AJN |
RC combination you speak of, is a low pass filter. "If I have a micro controller I would track those peak values". Well, if you had a fast enough micro controller, you could have done the multiplication also in it. A separate demodulator (y4 = y3 .* sin... ) would also not be required! DDC
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Oct 15, 2020 at 15:23 | comment | added | Newton Nadar | But I can get it by simply a sample and hold circuit ,with proper RC combination or If I have a micro controller I would track those peak values .Then why a low pass filter? Please explain @AJN | |
Oct 15, 2020 at 15:19 | comment | added | AJN | Thrid graph has two lines; a blue line and a red line. the red line is the output of the LPF. blue line is the input to the LPF. | |
Oct 15, 2020 at 15:18 | comment | added | Peter Smith | 'Tracking the peak voltages... ". What circuit would you use to do that? (Hint - its a filter). | |
Oct 15, 2020 at 15:08 | history | edited | Newton Nadar | CC BY-SA 4.0 |
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Oct 15, 2020 at 15:03 | comment | added | Newton Nadar | Yes Sir, The third wave is the wave after demodulating. \ i.e. m(t)*sin(fc*t) | |
Oct 15, 2020 at 15:02 | comment | added | Colin | @NewtonNadar, no, they're not, the top one is a fairly clean sinusoid, the bottom one is a sinusoid with some modulation superimposed on it, unless we're looking at different images. | |
Oct 15, 2020 at 15:00 | comment | added | Newton Nadar | @Colin But the graph are same.I mean the peaks | |
Oct 15, 2020 at 14:59 | history | undeleted | Newton Nadar | ||
Oct 15, 2020 at 14:55 | history | deleted | Newton Nadar | via Vote | |
Oct 15, 2020 at 14:53 | comment | added | Colin | It looks like it has some high frequency content in it too @NewtonNadar | |
Oct 15, 2020 at 14:52 | comment | added | Newton Nadar | @user253751 no it just seams to be scaled to 2 . | |
Oct 15, 2020 at 14:51 | comment | added | Newton Nadar | LPF at demodulator | |
Oct 15, 2020 at 14:51 | history | edited | Newton Nadar | CC BY-SA 4.0 |
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Oct 15, 2020 at 14:51 | comment | added | Criticizing Israel not allowed | You tell me, whether the first graph is the same as the third graph. | |
Oct 15, 2020 at 14:51 | comment | added | Criticizing Israel not allowed | which LPF where? | |
Oct 15, 2020 at 14:46 | history | asked | Newton Nadar | CC BY-SA 4.0 |