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Oct 16, 2020 at 16:58 vote accept Newton Nadar
Oct 16, 2020 at 16:58 comment added Newton Nadar Thank you understood the problem with peak detector .
Oct 16, 2020 at 16:57 vote accept Newton Nadar
Oct 16, 2020 at 16:58
Oct 15, 2020 at 20:26 history edited JRE CC BY-SA 4.0
added 8 characters in body; edited title
S Oct 15, 2020 at 17:27 history suggested AJN CC BY-SA 4.0
code formatting and spelling
Oct 15, 2020 at 16:02 answer added glen_geek timeline score: 1
Oct 15, 2020 at 16:00 review Suggested edits
S Oct 15, 2020 at 17:27
Oct 15, 2020 at 15:56 comment added AJN @NewtonNadar a peak detector would not work for suppressed carrier. During the negative cycles, the message is sitting in the valleys, not the peaks! Look carefully at the blue line in the third graph, particularly between 6 and 12 on the x axis.
Oct 15, 2020 at 15:54 comment added Criticizing Israel not allowed @NewtonNadar Would you say that tracking the peaks is... a type of low-pass filter?
Oct 15, 2020 at 15:51 answer added AJN timeline score: 1
Oct 15, 2020 at 15:46 comment added AJN @NewtonNadar Why does the code use sind instead of sin ? sind is very likely the wrong function to use in this context.
Oct 15, 2020 at 15:45 comment added AJN RC combination you speak of, is a low pass filter. "If I have a micro controller I would track those peak values". Well, if you had a fast enough micro controller, you could have done the multiplication also in it. A separate demodulator (y4 = y3 .* sin...) would also not be required! DDC
Oct 15, 2020 at 15:23 comment added Newton Nadar But I can get it by simply a sample and hold circuit ,with proper RC combination or If I have a micro controller I would track those peak values .Then why a low pass filter? Please explain @AJN
Oct 15, 2020 at 15:19 comment added AJN Thrid graph has two lines; a blue line and a red line. the red line is the output of the LPF. blue line is the input to the LPF.
Oct 15, 2020 at 15:18 comment added Peter Smith 'Tracking the peak voltages... ". What circuit would you use to do that? (Hint - its a filter).
Oct 15, 2020 at 15:08 history edited Newton Nadar CC BY-SA 4.0
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Oct 15, 2020 at 15:03 comment added Newton Nadar Yes Sir, The third wave is the wave after demodulating. \ i.e. m(t)*sin(fc*t)
Oct 15, 2020 at 15:02 comment added Colin @NewtonNadar, no, they're not, the top one is a fairly clean sinusoid, the bottom one is a sinusoid with some modulation superimposed on it, unless we're looking at different images.
Oct 15, 2020 at 15:00 comment added Newton Nadar @Colin But the graph are same.I mean the peaks
Oct 15, 2020 at 14:59 history undeleted Newton Nadar
Oct 15, 2020 at 14:55 history deleted Newton Nadar via Vote
Oct 15, 2020 at 14:53 comment added Colin It looks like it has some high frequency content in it too @NewtonNadar
Oct 15, 2020 at 14:52 comment added Newton Nadar @user253751 no it just seams to be scaled to 2 .
Oct 15, 2020 at 14:51 comment added Newton Nadar LPF at demodulator
Oct 15, 2020 at 14:51 history edited Newton Nadar CC BY-SA 4.0
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Oct 15, 2020 at 14:51 comment added Criticizing Israel not allowed You tell me, whether the first graph is the same as the third graph.
Oct 15, 2020 at 14:51 comment added Criticizing Israel not allowed which LPF where?
Oct 15, 2020 at 14:46 history asked Newton Nadar CC BY-SA 4.0