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Nov 4, 2020 at 5:23 vote accept Sourabh Misal
Nov 4, 2020 at 5:23 vote accept Sourabh Misal
Nov 4, 2020 at 5:23
Nov 4, 2020 at 5:23 vote accept Sourabh Misal
Nov 4, 2020 at 5:23
Nov 1, 2020 at 4:26 comment added Sourabh Misal @PaulGhobril yes, I realized it, I was doing a silly mistake of taking 2 mA as 2/10k instead of 2/1k and screwed it up
Oct 31, 2020 at 12:40 answer added Hilmar timeline score: 2
Oct 31, 2020 at 12:21 answer added Jan Eerland timeline score: 1
Oct 30, 2020 at 15:33 comment added Paul Ghobril @SourabhMisal your equation is correct and gives 12.5V. How are you getting the 8.5V?
Oct 30, 2020 at 14:48 vote accept Sourabh Misal
Nov 4, 2020 at 5:23
Oct 30, 2020 at 14:24 comment added Sourabh Misal Using nodal analysis and KCL with node at R1, I got this equation: 2 - (V1/10k) + ((5 - V1)/10k) = 0
Oct 30, 2020 at 14:21 history edited Sourabh Misal CC BY-SA 4.0
added 168 characters in body
Oct 30, 2020 at 14:15 comment added Sourabh Misal Ok, sorry for it, I will show it in a while
Oct 30, 2020 at 14:05 answer added Andy aka timeline score: 4
Oct 30, 2020 at 14:03 comment added Elliot Alderson This is not a homework solution service. We expect you to show your work and ask a specific question if you get stuck.
Oct 30, 2020 at 13:58 history asked Sourabh Misal CC BY-SA 4.0