I recently read this article on buttonswitch debouncing: A Guide to Debouncing - Part 2, or, How to Debounce a Contact in Two Easy Pages, by Jack Ganssle.
The article is on choosing the correct resistor and capacitor for your debounce circuit.
In the article, after calculating a (seemingly good) value of one of the resistor he goes on to say this :
But. the analysis ignores the gate's input leakage current. A CMOS device like the 74AHCT14 dribbles about a microamp from the inputs. That 180K resistor will bias the input up to .18 volts, uncomfortably close to the gate's best-case switching point of 0.5 volt. Change C to 1 µF and R2 is now 18K.
I am only beginning with electronics, so I can only guess what thatsthat's supposed to mean. And my best guess is that the leakage current is somehow effectingaffecting us in a bad way.
It will be a big help if someone can give me an explanation on what this section. I prefer to know what I am doing, if I am doing it.