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Math Keeps Me Busy
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"Previous circuits in the class have had V_out taken from the collector, which made it easy to derive an expression for V_out after multiple voltage divisions."

The last stage is an emitter follower (also known as a common collector amplifier). The emitter voltage closely follows the base voltage less one \$V_{BE}\$. The base voltage for the last stage is clearly \$V_{OUT}\$ of the previous stage.

"Additionally, is there any way that I can calculate the resistor values? Or should I load the circuit up in a Spice program and guess resistors until I get an acceptable A_mb and f_L?"

The voltage gain of a common emitter amplifier can be calculated from \$\frac{R_L}{R_E + R_e}\$ where \$R_e\$ is the intrinsic emitter resistance. If \$R_E\$ is large, \$R_e\$ can be ignored. Otherwise, \$R_e\$ can be calculated from \$I_E\$.

"Previous circuits in the class have had V_out taken from the collector, which made it easy to derive an expression for V_out after multiple voltage divisions."

The last stage is an emitter follower (also known as a common collector amplifier). The emitter voltage closely follows the base voltage less one \$V_{BE}\$. The base voltage for the last stage is clearly \$V_{OUT}\$ of the previous stage.

"Previous circuits in the class have had V_out taken from the collector, which made it easy to derive an expression for V_out after multiple voltage divisions."

The last stage is an emitter follower (also known as a common collector amplifier). The emitter voltage closely follows the base voltage less one \$V_{BE}\$. The base voltage for the last stage is clearly \$V_{OUT}\$ of the previous stage.

"Additionally, is there any way that I can calculate the resistor values? Or should I load the circuit up in a Spice program and guess resistors until I get an acceptable A_mb and f_L?"

The voltage gain of a common emitter amplifier can be calculated from \$\frac{R_L}{R_E + R_e}\$ where \$R_e\$ is the intrinsic emitter resistance. If \$R_E\$ is large, \$R_e\$ can be ignored. Otherwise, \$R_e\$ can be calculated from \$I_E\$.

Source Link
Math Keeps Me Busy
  • 27.8k
  • 5
  • 25
  • 87

"Previous circuits in the class have had V_out taken from the collector, which made it easy to derive an expression for V_out after multiple voltage divisions."

The last stage is an emitter follower (also known as a common collector amplifier). The emitter voltage closely follows the base voltage less one \$V_{BE}\$. The base voltage for the last stage is clearly \$V_{OUT}\$ of the previous stage.