Timeline for Why does the voltage drop when I connect an 8 ohms 1 watt speaker, specifically the source to the circuit is GPIO pin output voltage?
Current License: CC BY-SA 4.0
24 events
when toggle format | what | by | license | comment | |
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Jan 6, 2021 at 14:18 | history | became hot network question | |||
Jan 6, 2021 at 11:07 | vote | accept | GKN | ||
Jan 6, 2021 at 11:07 | vote | accept | GKN | ||
Jan 6, 2021 at 11:07 | |||||
Jan 6, 2021 at 10:14 | answer | added | JRE | timeline score: 10 | |
Jan 6, 2021 at 9:43 | comment | added | Math Keeps Me Busy | @gajanankaknale, given that information, I can definitely say that you are exceeding the ratings for that chip, and you risk damage to the chip. That gpio pin, and there are a number of different ones on that chip with different capabilities, cannot drive your 8\$\Omega\$ speaker. | |
Jan 6, 2021 at 9:32 | history | edited | Math Keeps Me Busy | CC BY-SA 4.0 |
identified chip with GPIO pin
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Jan 6, 2021 at 8:51 | answer | added | Simon B | timeline score: 4 | |
Jan 6, 2021 at 8:39 | answer | added | Justme | timeline score: 5 | |
Jan 6, 2021 at 7:25 | comment | added | GKN | The GPIO output pin is of IC "BlueNRG-1" Which im using for wireless bell application | |
Jan 6, 2021 at 7:22 | comment | added | mhaselup | GPIO pin on a RPi is only good for 16 mA. You cannot use it to supply power to the rest of your circuit directly and you may damage the GPIO with this arrangement. | |
Jan 6, 2021 at 7:19 | comment | added | Math Keeps Me Busy | Thank you for the new picture, but it still is not clear what component or board the GPIO is a pin of. Without knowing what the IC or board is, I cannot tell whether you are attempting to use more current from it than it is capable of. My guess is that you are, and that you will not only get poor volume, but may be damaging your IC or board. | |
Jan 6, 2021 at 7:16 | history | edited | JRE | CC BY-SA 4.0 |
added 14 characters in body
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Jan 6, 2021 at 7:15 | comment | added | GKN | @MathKeepsMeBusy can u check the new image i uploaded.May be it is clear now | |
Jan 6, 2021 at 7:12 | history | edited | GKN | CC BY-SA 4.0 |
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Jan 6, 2021 at 7:11 | answer | added | Frog | timeline score: 2 | |
Jan 6, 2021 at 7:08 | history | edited | GKN | CC BY-SA 4.0 |
deleted 44 characters in body
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Jan 6, 2021 at 6:56 | history | edited | JRE | CC BY-SA 4.0 |
deleted 7 characters in body; edited title
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Jan 6, 2021 at 6:41 | comment | added | StarCat | From your description and the included schematic it’s not clear where the GPIO of the Nucleo board is connected. Please edit the schematic to show that. Also, the “power supply” (1k resistor + zener) to the BT66T looks like it will not work very well when there’s any load on it. Consider putting a real 3.3V voltage stabilizer in its place or connect it to the Nucleo’s supply. | |
Jan 6, 2021 at 6:41 | comment | added | copper.hat | This is just the circuit from the BT66T datasheet. You need to show how you have connected your nucwhatever board. | |
Jan 6, 2021 at 6:27 | comment | added | GKN | "nucleo board" just consider its a 3.3 volts source. i'm activating GPIO pin for 5 seconds through program, which gives you 3.2volts output for a period of 5 seconds,Which im giving it to the circuit as a voltage source. | |
Jan 6, 2021 at 6:25 | comment | added | Math Keeps Me Busy | "When i connect the GPIO output pin 3.2 volts as a source to the circuit". You don't show a device with a GPIO pin in your circuit diagram. Generally, GPIO pins do not provide much current. Not only may you not get much sound, you may damage the component with the GPIO pin. | |
Jan 6, 2021 at 6:20 | comment | added | niko20 | What is "nuclei board" and what GPIO pin are you talking about? And "connecting " it , where? This post is very confusing. | |
Jan 6, 2021 at 6:18 | review | First posts | |||
Jan 6, 2021 at 10:50 | |||||
Jan 6, 2021 at 6:15 | history | asked | GKN | CC BY-SA 4.0 |