Timeline for Why does the voltage drop when I connect an 8 ohms 1 watt speaker, specifically the source to the circuit is GPIO pin output voltage?
Current License: CC BY-SA 4.0
6 events
| when toggle format | what | by | license | comment | |
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| Jan 7, 2021 at 7:52 | comment | added | the busybee | I know. I looked at the very first version, and any after it. My claim still holds true. | |
| Jan 7, 2021 at 7:51 | comment | added | Frog | The question has been updated at least once since I responded to it. | |
| Jan 7, 2021 at 7:06 | comment | added | the busybee | But the OP clearly stated that the circuit (as a whole) was sourced from the GPIO. -- The first hit on any web search reveals the description of the BT66T, which gives its supply current as 1µA. So it's still not the IC, you might call the resistor-zener combination to have a "high" current. I expect at least a little bit of thinking and research. | |
| Jan 7, 2021 at 6:43 | comment | added | Frog | At the time of writing The speaker was shown driven off a 9V supply | |
| Jan 6, 2021 at 12:04 | comment | added | the busybee | It is not the BT66T that needs that much current, it is the speaker. It has 8 ohms. | |
| Jan 6, 2021 at 7:11 | history | answered | Frog | CC BY-SA 4.0 |