Timeline for Where has this current gone in my current-voltage converter?
Current License: CC BY-SA 4.0
17 events
| when toggle format | what | by | license | comment | |
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| Dec 25, 2021 at 14:31 | answer | added | AnalogKid | timeline score: 1 | |
| Dec 24, 2021 at 22:39 | answer | added | Circuit fantasist | timeline score: 2 | |
| Sep 22, 2021 at 11:04 | vote | accept | Antonio51 | ||
| Sep 8, 2021 at 0:53 | answer | added | Simon Fitch | timeline score: 2 | |
| Sep 7, 2021 at 22:45 | answer | added | Tesla23 | timeline score: 2 | |
| Sep 7, 2021 at 22:14 | answer | added | Antonio51 | timeline score: 2 | |
| Sep 7, 2021 at 19:15 | comment | added | Antonio51 | Well, to help, I will give a tip, "redraw" the "power supplies" ... | |
| Sep 7, 2021 at 19:03 | comment | added | jonk | Thanks for the correction. I mispoke when I wrote "offset." I meant bias! (Edited and fixed!) Each input has its bias current. The schematic on page 2 illustrates why it must. They also have an offset (difference between them.) In the ideal case, there would be zero bias and zero offset currents and no voltage offset, either. The idea for your current to voltage converter is that the output must slew in order to pull away the current you inject into the node (plus or minus whatever bias current the input causes.) But that has no never-mind with respect to the other op amp input bias current. | |
| Sep 7, 2021 at 19:02 | history | edited | SamGibson♦ | CC BY-SA 4.0 |
Small grammar changes to help readability. Removed barely-related tags.
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| Sep 7, 2021 at 19:02 | comment | added | Antonio51 | Ok for the current flowing in R4 ... and R1. Ok also for the bias input current (almost 0 nA) that flows between (+) and ground. But "where" is my 10uA that flows in the picture at left ? How can one rewire this schematic to see these 10 uA ? | |
| Sep 7, 2021 at 19:01 | answer | added | Transistor | timeline score: 5 | |
| Sep 7, 2021 at 18:59 | comment | added | jonk | No. You should expect an bias current from that op amp input. But otherwise unrelated to the current you are injecting at the other input. The other input itself may also have its bias current, too (and it will since it must in order to work.) This last aspect will confound your transimpedance design a bit, too. I recommend that you study the input stage of your given bipolar op amp. | |
| Sep 7, 2021 at 18:58 | comment | added | Antonio51 | Yes ... I am a "newbie". Because of the way I wire the current-voltage converter. I "expect" 10 uA in the wire (+) op amp to ground. | |
| Sep 7, 2021 at 18:57 | answer | added | Andy aka | timeline score: 3 | |
| Sep 7, 2021 at 18:52 | comment | added | jonk | Why are you pointing at the (+) op amp input node with respect to a current there. Do you expect one that matches your earlier measured current? | |
| Sep 7, 2021 at 18:51 | history | edited | Transistor | CC BY-SA 4.0 |
added 5 characters in body
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| Sep 7, 2021 at 18:45 | history | asked | Antonio51 | CC BY-SA 4.0 |