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Mar 16, 2022 at 3:29 answer added Kuba hasn't forgotten Monica timeline score: 1
Mar 16, 2022 at 0:06 comment added Ilya @AhmetAtcı add your conclusions/observations as your own reply below and select it as a chosen answer. Glad you got it fixed.
Mar 15, 2022 at 22:49 comment added Ahmet Atcı Thanks everyone adding a small cap solves problem everywhere with resistor divider and opamp output. I guess instant switching of adc scan creates current rush to the sample cap. And adding a cap to the input solves problem. Thanks.
Mar 15, 2022 at 22:00 comment added Kevin White Just add a small capacitor at the input of the MCU to supply the charge needed for the input sampling capacitor. Maybe 1000pF.
Mar 15, 2022 at 21:58 comment added Kartman What happens if you put a 10nF cap on the adc input? Assuming your inputs are low frequency?
Mar 15, 2022 at 21:56 history edited Kartman CC BY-SA 4.0
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Mar 15, 2022 at 21:51 comment added Ilya 1M-200k is crazily much. Even if you have a pair of picofarads of input capacitance, you have a whole RC circuit with massive resistor. Try making op amp buffer (voltage follower) and feeding it directly into input pin without any resistor and see what happens
Mar 15, 2022 at 21:07 comment added Ahmet Atcı When using resistor divider i get that noise 352mVpp with 1M-200K resistor values. But when i use opamp with 50 ohm serial resistor I get 150mVpp peak. Problem still same with opamp.
Mar 15, 2022 at 21:02 comment added Klas-Kenny Every time the ADC samples, the pin will draw some current to charge the internal capacitor of the sample-and-hold circuit. What series resistance do you have on the inputs?
S Mar 15, 2022 at 21:00 review First questions
Mar 15, 2022 at 22:15
S Mar 15, 2022 at 21:00 history asked Ahmet Atcı CC BY-SA 4.0