Timeline for Using Ohm's law in a simple circuit with a DC power adapter
Current License: CC BY-SA 4.0
7 events
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| Nov 19, 2022 at 14:24 | comment | added | brhans | @Dan also because your circuit is so simple, not only is your adapter connected in parallel with the resistor, it's also connected in series. The current flowing through elements in series is always the same current (just as the voltage across elements in parallel is always the same voltage). Whatever current flows "into" the resistor must also flow "out" of the resistor, and similarly whatever current flows out of the adapter must also flow into the adapter on the other side. | |
| Nov 19, 2022 at 2:50 | vote | accept | Dan | ||
| Nov 19, 2022 at 0:59 | comment | added | brhans | @Dan for [1], you didn't specify a voltage - you only specified the current (1A) and resistance (1k). The only way you can get 1A to flow through a 1k resistor is if you apply 1000V to the resistor. | |
| Nov 19, 2022 at 0:19 | comment | added | Dan | for [1], are you saying we can use the total amp provided by the adaptor to calculate the voltage after resistor? so V = 1 A . 1k = 1000V , that doesn't seem right. I think we need to use the amp used by resistor? | |
| Nov 18, 2022 at 15:17 | history | edited | brhans | CC BY-SA 4.0 |
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| Nov 18, 2022 at 10:56 | history | edited | winny | CC BY-SA 4.0 |
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| Nov 18, 2022 at 6:45 | history | answered | brhans | CC BY-SA 4.0 |