Timeline for Charging a circuit to around 10kV from 3V (two AA batteries) for discharge over 20msec
Current License: CC BY-SA 3.0
24 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| S Jun 19, 2013 at 8:08 | history | bounty ended | PeterJ | ||
| S Jun 19, 2013 at 8:08 | history | notice removed | PeterJ | ||
| Jun 18, 2013 at 20:01 | history | tweeted | twitter.com/#!/StackElectronix/status/347081686967779329 | ||
| Jun 14, 2013 at 15:05 | history | protected | clabacchio | ||
| Jun 14, 2013 at 10:26 | answer | added | Andy aka | timeline score: 12 | |
| Jun 14, 2013 at 9:27 | comment | added | Andy aka | Two questions; is the load going to be applied once the output cap is charged to the required voltage AND you say "the output current will be current limited to a maximum of 20mA" - is this something that is done with external circuits or are you expecting this to be inherent in the solution? | |
| S Jun 12, 2013 at 7:01 | history | bounty started | PeterJ | ||
| S Jun 12, 2013 at 7:01 | history | notice added | PeterJ | Improve details | |
| Jun 12, 2013 at 7:00 | history | edited | PeterJ | CC BY-SA 3.0 |
Remove some unnecessary text
|
| Apr 19, 2013 at 18:43 | comment | added | starblue | In the appendix of this document is a circuit diagram for a Geiger counter, including generation of the high voltage. It might give you some ideas, though at several hundred volts it is still far away from what you want to achieve. | |
| Apr 18, 2013 at 17:30 | answer | added | John R. Strohm | timeline score: 4 | |
| Apr 18, 2013 at 17:28 | answer | added | placeholder | timeline score: 4 | |
| Apr 18, 2013 at 17:10 | answer | added | Brad | timeline score: 0 | |
| Apr 18, 2013 at 13:27 | history | edited | bjarkef | CC BY-SA 3.0 |
added 14 characters in body; edited title
|
| Apr 18, 2013 at 13:25 | comment | added | bjarkef | @LeonHeller: Typical AA batteries provide around 1500 mAh at 1.5V, which equals around 8100 Joules. As DaveTweet says, I require 20mA for 20msec at 10kV, which is 4 Joules. So I should be able to discharge the circuit around 2000 times with only a single AA battery. And as the circuit can charge arbitrarily slow, the current drawn from the battery can be as low as the battery requires. I don't see the problem here? | |
| Apr 18, 2013 at 13:25 | comment | added | PeterJ | @bjarkef, I gave you an upvote to cancel that because this will have a solution. But just re-reading the question (without comments) you probably should edit to include you're charging a cap and cycle time doesn't matter much. It does read a bit like you're expecting it to deliver 20mA @ 10kV which even for a short time would be impossible without the cap. | |
| Apr 18, 2013 at 13:10 | review | Close votes | |||
| Apr 18, 2013 at 16:10 | |||||
| Apr 18, 2013 at 13:02 | comment | added | bjarkef | @DaveTweed: I mean milli (mA not µA). I can tolerate any voltage drop, it can even drop to 3V before charging up to 10kV again. It is perfectly okay with a long charge time, my problem is how to actually design the circuit which will charge a capacitor with that high a voltage from batteries. | |
| Apr 18, 2013 at 13:01 | comment | added | Dave Tweed | @LeonHeller: 200W * 50ms = 10J. A pair of AAs should be able to do that 100s of times. | |
| Apr 18, 2013 at 12:58 | comment | added | Dave Tweed | How much voltage droop can you tolerate during the discharge cycle? This will determine the size of the capacitor you need. Then you can figure out how long it would take a couple of AAs to charge it. Even once charged up, it will require several minutes between dicharges to recover -- and that's assuming 1A draw from the batteries, which is a lot. | |
| Apr 18, 2013 at 12:53 | comment | added | Leon Heller | You won't get 100 W from two AA cells! | |
| Apr 18, 2013 at 12:49 | comment | added | pjc50 | (a) That's a potentially lethal voltage/current combination. (b) That's also 400W, no mean amount of power. (c) I'd start from various DIY tesla or spark projects: rmcybernetics.com/projects/DIY_Devices/homemade_tesla_coil.htm | |
| Apr 18, 2013 at 12:46 | comment | added | Dave Tweed | Do you mean milliamps (i.e., 200W) or microamps (more like 0.2W)? | |
| Apr 18, 2013 at 12:36 | history | asked | bjarkef | CC BY-SA 3.0 |