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evildemonic
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  • R2 is likely to cause more problems than it would solve. I would get rid of it, but see the next point...
  • The emitter of the BJT won't go above about 2.7 V. If it did, the base-emitter junction would be reverse biased and the transistor would be off.
  • Look into opto-isolators/solid-state relays. You should have no trouble finding one that is through-hole and can work with 3.3 V and a single resistor. EXAMPLE There are also gate driver ICs for MOSFETs that can work off 3.3 V logic. These often provide their won charge-pump so you don't even need to provide the 5 V (or whatever) yourself.

If you can't invert the PWM logic, you just need to add an extra transistor. Something like this could work:

schematic

simulate this circuit – Schematic created using CircuitLab

  • R2 is likely to cause more problems than it would solve. I would get rid of it, but see the next point...
  • The emitter of the BJT won't go above about 2.7 V. If it did, the base-emitter junction would be reverse biased and the transistor would be off.
  • Look into opto-isolators/solid-state relays. You should have no trouble finding one that is through-hole and can work with 3.3 V and a single resistor. EXAMPLE There are also gate driver ICs for MOSFETs that can work off 3.3 V logic. These often provide their won charge-pump so you don't even need to provide the 5 V (or whatever) yourself.
  • R2 is likely to cause more problems than it would solve. I would get rid of it, but see the next point...
  • The emitter of the BJT won't go above about 2.7 V. If it did, the base-emitter junction would be reverse biased and the transistor would be off.
  • Look into opto-isolators/solid-state relays. You should have no trouble finding one that is through-hole and can work with 3.3 V and a single resistor. EXAMPLE There are also gate driver ICs for MOSFETs that can work off 3.3 V logic. These often provide their won charge-pump so you don't even need to provide the 5 V (or whatever) yourself.

If you can't invert the PWM logic, you just need to add an extra transistor. Something like this could work:

schematic

simulate this circuit – Schematic created using CircuitLab

added 184 characters in body
Source Link
evildemonic
  • 9.5k
  • 2
  • 28
  • 48
  • R2 is likely to cause more problems than it would solve. I would get rid of it, but see the next point...
  • The emitter of the BJT won't go above about 2.7 V. If it did, the base-emitter junction would be reverse biased and the transistor would be off.
  • Look into opto-isolators/solid-state relays. You should have no trouble finding one that is through-hole and can work with 3.3 V and a single resistor. EXAMPLE There are also gate driver ICs for MOSFETs that can work off 3.3 V logic. These often provide their won charge-pump so you don't even need to provide the 5 V (or whatever) yourself.
  • R2 is likely to cause more problems than it would solve. I would get rid of it, but see the next point...
  • The emitter of the BJT won't go above about 2.7 V. If it did, the base-emitter junction would be reverse biased and the transistor would be off.
  • Look into opto-isolators/solid-state relays. You should have no trouble finding one that is through-hole and can work with 3.3 V and a single resistor.
  • R2 is likely to cause more problems than it would solve. I would get rid of it, but see the next point...
  • The emitter of the BJT won't go above about 2.7 V. If it did, the base-emitter junction would be reverse biased and the transistor would be off.
  • Look into opto-isolators/solid-state relays. You should have no trouble finding one that is through-hole and can work with 3.3 V and a single resistor. EXAMPLE There are also gate driver ICs for MOSFETs that can work off 3.3 V logic. These often provide their won charge-pump so you don't even need to provide the 5 V (or whatever) yourself.
Source Link
evildemonic
  • 9.5k
  • 2
  • 28
  • 48

  • R2 is likely to cause more problems than it would solve. I would get rid of it, but see the next point...
  • The emitter of the BJT won't go above about 2.7 V. If it did, the base-emitter junction would be reverse biased and the transistor would be off.
  • Look into opto-isolators/solid-state relays. You should have no trouble finding one that is through-hole and can work with 3.3 V and a single resistor.