Timeline for How can I handle regenerative braking when the lithium-ion battery is full?
Current License: CC BY-SA 4.0
10 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Oct 1, 2023 at 17:00 | vote | accept | Maple | ||
| Sep 14, 2023 at 3:25 | comment | added | Maple | You've now waded into waters way over my head. I think R3 already made it not exactly Darlington. I was looking at Q1 as more of pre-amplifier stage that would give better precision to voltage threshold. But then again, I am not an analog guy. | |
| Sep 14, 2023 at 3:08 | comment | added | Jasen Слава Україні | that's an interesting idea, usually with a larlinton arrangement like this the goal is to get current flowign through the load, but there's no reason not to split the load into two parts, the tricky bit would be chosing the right ratio, perhaps 10:1 or 30:1 depending on the beta of Q2 | |
| Sep 13, 2023 at 21:01 | comment | added | Maple | I was wondering about collector connection to R1 too. Also, I've updated the question with another requirement. Would be nice to add inhibit input to this circuit to prevent it from activating when charger is connected. Since we do not have an access to charging socket the signal will most likely be coming from reed relay, so it can be either positive or ground. | |
| Sep 13, 2023 at 16:19 | comment | added | Criticizing Israel not allowed | pardon me if it's a stupid idea, but connecting Q1's collector to the + through another resistor (maybe also 10k, low power) would allow Q2's collector voltage to drop further, so R1 dissipates more and Q2 dissipates less? I haven't checked this idea in a simulator | |
| Sep 13, 2023 at 14:10 | comment | added | Jasen Слава Україні | the poster was worried about slowness, this is the fastest circuit, | |
| Sep 13, 2023 at 11:09 | comment | added | tobalt | Usually you'd use a hysteretic comparator and mosfet. That way, there is essentially no dissipation in the transistor and all of it in the power resistor which is easier to manage. | |
| Sep 13, 2023 at 7:20 | comment | added | BeB00 | You could fix the issue by using an opamp instead of a zener and an N mosfet, giving a sharper switching action - you could probably get it down to 1% power in the transistor, maybe less | |
| Sep 13, 2023 at 7:12 | comment | added | BeB00 | I think this is the best circuit so far - I think C1 is interesting, but I might leave it out and rely only on the voltage action. I wonder if there might be a better way of reducing the power requirement for the transistor though, 25% is still a pretty huge amount | |
| Sep 12, 2023 at 23:06 | history | answered | Jasen Слава Україні | CC BY-SA 4.0 |