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Nov 28, 2018 at 21:34 comment added Jorge Leon Excuse me but how did you get 529 as your Z base?
May 26, 2013 at 21:35 vote accept James Mitch
May 26, 2013 at 14:22 comment added Quantum Magician \$B\$ is the imaginary part of the admittance (\$Y\$), and \$G\$ is the real part. Please, remember that the admittance (\$Y\$) is given as: \$Y=G+jB\$. Read: en.wikipedia.org/wiki/Admittance
May 26, 2013 at 11:29 comment added James Mitch Thanks, that was a good answer. But I have one last question. How can I calculate the Shunt Charging (B) and the Shunt Conductance (G)?
May 25, 2013 at 19:23 history edited Nick Alexeev CC BY-SA 3.0
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S May 25, 2013 at 19:07 review Late answers
May 25, 2013 at 19:23
S May 25, 2013 at 19:07 review First posts
May 25, 2013 at 21:23
May 25, 2013 at 18:48 history answered Quantum Magician CC BY-SA 3.0