Timeline for How does all (well most of) the flux in the primary side get into the secondary side in a transformer?
Current License: CC BY-SA 4.0
4 events
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| Mar 12 at 11:46 | comment | added | Andy aka | I don't think the same restriction applies to B fields <-- you can use the concept of a parallel resistor representing air's reluctance and that will satisfy the equivalent Kirchhoff law @JonathanLee | |
| Mar 12 at 10:21 | comment | added | Andy aka | @JonathanLee H will be weaker in the secondary by a small amount. B and H are proportional i.e. \$B = \mu_e\cdot H\$. B isn't something that I would say flows (other than in my analogy). | |
| Mar 12 at 9:11 | comment | added | Jonathan Lee | So is the description in the question incorrect, where B is proportional to H, and H is smaller in the secondary than primary (H created from the primary side)? As for as I know, B is just H multiplied by permeability? Does B need to flow along a path similar to current? In KCL, the current along a closed path must be constant, I don't think the same restriction applies to B fields? | |
| Mar 12 at 8:47 | history | answered | Andy aka | CC BY-SA 4.0 |