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Sep 9 at 11:33 comment added Andy aka It seems that your comments have nothing to do with this post and, I don't understand why you are making them. Maybe you should make an answer and explain what you are trying to say?
Sep 9 at 0:06 comment added Tim Williams Or, if you've read the linked answer -- could you comment on it, what's missing from the simulation, or what's unrealistic about the choice and connection of components, or incorrect about the explanation text?
Sep 9 at 0:06 comment added Tim Williams Andy, I'm not sure what more I can explain; I know you know about this, you're no stranger to SMPS design, and you would never suggest to build say a boost converter without the output capacitor placed nearby. Somehow, I am patently unable to communicate this idea to you here, but I cannot ascertain why. (Could someone else perhaps comment what I'm missing?)
Sep 8 at 23:47 comment added Andy aka That makes no sense. Maybe it's time to explain how the capacitor proposed in your comment helps.
Sep 8 at 21:16 comment added Tim Williams Wire doesn't have to be looped around to exhibit inductance, In fact inductance is a necessary consequence of nonzero length. The Q1-D1-cap loop can still generate peak voltage, worth noting as we don't know how long that +12V connection is here, it might be 10mm or 10m. More comments along these lines here: electronics.stackexchange.com/questions/175390/…
Sep 8 at 19:47 comment added Andy aka I think that's a red herring. The current in the inductance of the wound device finds a local circulatory path via the diode and a bypass capacitor is irrelevant. Please review what you are saying or justify why you think it's important.
Sep 8 at 18:43 comment added Tim Williams Note the diode is most effective when a bypass capacitor is placed nearby (+12V to GND).
Sep 8 at 15:59 vote accept Fábio Silva
Sep 8 at 15:43 history answered Andy aka CC BY-SA 4.0