I have a circuit that looks like the following. It appears to be simple-
What's the thevenin equivalent? I can't seem to simplify it as there are no common nodes that any of the resistors connect.
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2\$\begingroup\$ I would redraw this circuit first to clearly see what is parallel to what \$\endgroup\$– Eugene Sh.Commented Jun 30, 2020 at 17:35
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1\$\begingroup\$ R5 to R1 is as R4 to R2 - redraw to make the image simpler - this always helps. \$\endgroup\$– Andy akaCommented Jun 30, 2020 at 17:44
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\$\begingroup\$ If you redraw your schematic you will find that it is similar to a "Wheatstone bridge" (not invented by Wheatstone who only popularized another's invention) except that there is a resistor where a source usually is placed. It's a classic case suggesting that you memorize the \$\Delta-Y\$ conversions (both directions may be worth memorizing.) But it can also be solved out using nodal analysis, too. Are you familiar with nodal? \$\endgroup\$– jonkCommented Jun 30, 2020 at 19:32
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\$\begingroup\$ As others say, you can re-draw this to make it more clear. Also, this problem is often given with further condtions, like R1=R2=R4=R5. If you were given that information, you can simplify the circuit even further with a clever trick. \$\endgroup\$– The PhotonCommented Jun 30, 2020 at 20:52
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1 Answer
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Use the delta-wye transformation and then you’ll see parallel and series combinations of resistors you can reduce.
answered Jun 30, 2020 at 17:28
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1\$\begingroup\$ Works like a charm- thanks! \$\endgroup\$ Commented Jul 2, 2020 at 17:13