0
\$\begingroup\$

I need to buffer a 0-5V signal that is coming from a resistor network and being fed into an IC. When I feed it directly to the IC there is a loading effect and the value is changed specifically at 0V input the IC will source current out the input pin and produce a ~0.3V value.

My first thought was to use an Op Amp as a voltage follower. I have a TI-082 available and tried to use. I have a +24V and +5V sources available and using a single 24V supply for the op-amp works great for values from ~1.5-5V but anything under that and the output swings to the 24V supply voltage. I understand this is due to getting to close to the negative rail.

I next set up a +/-12V supply from my 24V source and everything in the 0-5V range was properly buffered, but the problem was I could no longer input it to the intended IC since the IC is powered by 24V and GND and the input is references to GND so to the IC the 0-5V was appearing as 12-17V.

Is there a way to make the op-amp go to 0V when hitting the negative rail? Forcing the bottom 1.5V to GND would be acceptable but output 24V is not. Alternatively, is there anyway to configure the +/-12V configuration to work despite the input being referenced to what would be the -12V line from the op-amp's perspective?

\$\endgroup\$
4
  • 1
    \$\begingroup\$ Use a Rail-to-Rail I/O op-amp. \$\endgroup\$
    – Majenko
    Commented Jun 27, 2014 at 20:53
  • \$\begingroup\$ If it's a +/-12V supply why is the opamp powered from 24V and Gnd? It would be normal to power it from +12V and -12V; in other words connect the 5V -ve to the 0V centre tap on the PSU and consider THAT not the -ve rail, as GND. (Having chosen it as GND you have to be consistent about it, use it as GND for input signals, output signals, CPU, etc) \$\endgroup\$
    – user16324
    Commented Jun 27, 2014 at 20:58
  • \$\begingroup\$ It's not a +/-12V supply, its a 24V supply. I split it to create the +/-12 while trying to find a solution. The voltage followed properly but then I couldn't connect it as needed because as you mentioned there were multiple "GND"s at that point \$\endgroup\$ Commented Jun 27, 2014 at 21:08
  • \$\begingroup\$ You need a supply that goes a little bit negative below your 0V and then use a rail-to-rail op-amp connected to this neg rail. I'd try and manufacture a +6V rail too - then it gives you more options with choosing the R2R op-amp. \$\endgroup\$
    – Andy aka
    Commented Jun 27, 2014 at 21:11

1 Answer 1

1
\$\begingroup\$

Here is a link to an article I wrote a while back about this class of problems.

A device such as the LM7705 or an inverting charge pump such as the LM2661 will generate the negative voltage needed for the amplifier to output 0 volts with 0 volts input

These devices will generate the negative voltage with reference to your circuit common.

\$\endgroup\$
1
  • \$\begingroup\$ This describes exactly the problem I am trying to solve and unfortunately it looks like I will have to buy more hardware or settle for the resistive loading effect. \$\endgroup\$ Commented Jun 30, 2014 at 20:08

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.