I have been doing a bit research on ceramic capacitors, as I need one for the output of my synchronous buck converter. And as its very common that ESR is not straight forwardly given in the data sheets, we have to calculate it ourselves by Dissipation Factor value given at a certain frequency (normally 120 Hz) for a certain capacitance value.
$$ESR = \dfrac{D \cdot F}{2 \pi f C}$$
For e.g if i have this ceramic capacitor I can calculate the ESR as
$$ \dfrac{0.05}{2 \pi \cdot 120 \cdot 470 \mu F} = 141m\Omega$$
(page 1 of data sheet, calculating for 470uF cap).
Now my question is, what if I am using this capacitor in my circuit at 100kHz? Its ESR should decrease right? As I think ESR should decrease with increasing the frequency. But the Dissipation factor increases with the increase in frequency as well. So how can one estimate the capacitor ESR at a high frequency? As there is no Frequency vs ESR OR Frequency vs D.F graphical relation given in the data sheets (I have gone through almost 100s of data sheets). So is there any way by which I can estimate the ESR of this capacitor at a higher frequency of 100kHz?
Actually I will be charging my battery cell with the help of my buck converter and I need the capacitor ESR to be less than 10mOhms, because that is my Battery cell's ESR (mentioned in the data sheet), so I am trying to look for a ceramic capacitor with a lower ESR than this, for minimizing my voltage ripple at the output.
Your helpful comments would be appreciated.
Thankyou!