5
\$\begingroup\$

I am trying to design a PLL and want to test it first in Matlab.

I have seen that the phase of the input and output are linearized, but I don't understand what is defined by the input/output phase.

Usually, a transfer function is the ratio of the input's voltage/current to the output voltage/current. However, this Wikipedia article gives the transfer function of a PLL as the ratio of two phases:

\$ \frac{\theta_O}{\theta_I} = \frac{K_P K_v F(s) } { s + K_P K_v F(s)} \$

where

  • \$\theta_O\$ is the output phase in radians

  • \$\theta_I\$ is the input phase in radians

  • \$K_P\$ is the phase detector gain in volts per radian

  • \$K_V\$ is the VCO gain in radians per volt-second

  • \$F(s)\$ is the loop filter transfer function (dimensionless)

* How do I interpret this transfer function ? *

\$\endgroup\$

2 Answers 2

2
\$\begingroup\$

IMPORTANT: the transfer function is an abstraction that tells basically what is the difference between the output (generally speaking) and the input (same as before); it's often used with voltages, but you can use what you want (also ice cream / fruit).

Then, just use the definition: as a Phase-Locked Loop (PLL)...

is a control system that generates an output signal whose phase is related to the phase of an input "reference" signal

...that ratio tells you what will be the phase of the output signal given the phase of the input signal.

The phase is well explained in the race car analogy: if you consider a sinusoidal signal as a dot going around in the euclidean circumference (counter-clockwise), the phase is the difference (in radians) between two signals (two points) in this circumference; or, for a signal, the distance from the 0 (rightmost point) of that circumference. In a more concrete way, is the "time" that has passed since when the signal has been the last time at value 0 while raising.

Since PLLs are circuits that try to synchronize clocks or signals in general, the phase is a good indicator of how much these signals are synchronized.

\$\endgroup\$
3
\$\begingroup\$

A key point not mentioned in the other answer is, when we talk about a "linearized" model, we're talking about small oscillating deviations about an operating point.

As clabacchio said, the point of a PLL is to generate an single-tone output whose output phase is aligned to the phase of a single-tone reference input, typically at a lower frequency. The linearized model tells us, if the phase of the input signal changes by a small amount, how much will the phase of the output change. Furthermore, the rate of change of the input is important, so we represent its phase by a phasor variable, and the transfer function tells us not just by how much the output phase changes, but how its change lags or leads the change in the phase of the input signal.

\$\endgroup\$
2
  • \$\begingroup\$ Yes, but if you think to clock signals, it's often used to raise the frequency. \$\endgroup\$
    – clabacchio
    Commented Jan 27, 2012 at 20:07
  • \$\begingroup\$ Sorry, I thought I said that...by single tone I don't mean strictly a sine wave, square waves or other strictly repetitive signals are also used. \$\endgroup\$
    – The Photon
    Commented Jan 27, 2012 at 20:18

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.