0
\$\begingroup\$

schematic

simulate this circuit – Schematic created using CircuitLab

I have made the above (useless) schematic in LTspice. This after running into issues with a full schematic. The idea is to let e pulse train pass to the 2nd voltage controlled switch if and only if the Condensator connected to the positive input of SW1 reaches at least a voltage of 1.5V

However, this did not seem to work so in a test case I connected SW1 both the positive and negative input to ground. (Which to my knowledge should make SW1 always open). I have just a few days of experience with LTspice so it might be that I'm missing something. I have however googled and this seemed to be the right way to do it.

The full schematic in LTspice is given below

LTspice Schematic

This results in next simulation:

Simulation of LTspice model

Does anybody know what I'm doing wrong? S1(SW2) is the MYSW and S2(SW1) is the UCSW. I can't seem to get it to work even if I change Vt to 15V.

\$\endgroup\$

1 Answer 1

0
\$\begingroup\$

Put a 1k resistor across the control terminals of S1.

Now see if you can figure out why this makes a difference.


A voltage-controlled switch is just that — sensitive to voltage only. It doesn't care whether that voltage is connected through a 10M resistor or a 1m resistor — since it draws no current, there's no voltage drop across the contacts of S2 in either state.

\$\endgroup\$
1
  • \$\begingroup\$ So basically because these switches neither have a leak current nor an infinital high resistance (open chain ) there is no voltage drop over S2. If you introduce a 'leak current' by placing a resistor in parallel the issue does get solved, thanks @Dave Tweed \$\endgroup\$ Commented Sep 25, 2018 at 6:56

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.