I was thinking of a design for bringing VCC+ and GND to a board through a PCB connector. VCC = 6 kV. It comes from external source towards a banana jack within a metal case. The first idea was to fit the PCB design into this case.
I don't find any PCB connector with 6 kV capable to support the 6 kV voltage difference from other connector with 0 V at the same PCB side. I have found some of them, Wurth, with 3.5 kV dielectric strength. This is the maximum I have found.
In this situation I thought that the material offered by my manufacturer could be a good insulator with 1.6mm --> 40 kV > 6 kV. So, if I put VCC on top side and GND on bottom side (I think of doing it this way) the connector dielectric will never fail.
But now my problem is that someone asks for me to put all the connectors at the TOP of the PCB: VCC+ and GND, in order to access both them by the same side. The connectors have only 3.5 kV of dielectric strength.
Is it possible to place the 2 connectors at top side of a PCB with these features: 6 kV between VCC+ connector and GND connector, being two connectors having a maximum voltage = 3.5kV according the manufacturer datasheet?
I need PCB connectors for supporting this 6 kV between them. I can't find any. I have looked for connectors at typical and non-typical distributors, without success. Is there a way to do this? How can I put connectors with this voltage difference between one connector and the other?
Clearance calculation does not take into account connector dielectric. I don't think it could be solved applying clearance or creepage calculations without taking into account the 3.5 kV connector dielectric strength.