Fusing an In-Wall LED Application

Question

I'm building my own PCB to power 8 in-wall LED's for a stairwell. I'd like to protect the LED's with fuses, but I'm unclear on how the voltage on fuses work. My specs are as follows:

LEDs: 5V, 600mA, 3W LED (x 8)

LED Driver Output: +5V, 5.0A, 35W DC

I think I understand how the amperage works with the fuses, but I'm not sure if the fuses need to be 5v or if they can be higher.

I'm not an electrical engineer, so I don't know what I'm doing, but here's where I'm at:

I have two questions.

1. Can I go with a higher voltage fuse such as this: https://www.amazon.com/dp/B00X772B3M/ref=cm_sw_r_sms_c_api_i_P9r3EbTMEDREB
2. Is there anything I'm missing in my circuit?

I appreciate any advice anyone can give.

Regards, TY

Answer 1

1. You can use a higher voltage rating fuse.

2. The schematic needs improvement. PTC is too slow to protect LEDs from overcurrent. Using a PTC to limit LED current is not as straightforward as it might seem. You need to add series resistor to limit the current. You can use a "led resistor calculator" for the values. For example: http://www.ohmslawcalculator.com/led-resistor-calculator

In your circuit depending on exact components you are wasting around 20 % on the series resistors. Consider using a dedicated LED driver, that adjusts the current or use a higher voltage and have several LEDs in series, so that smaller percentage of voltage is left over the resistor.