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I am trying to build a circuit using only encoders and decoders. This circuit will output the 1’s complement of 3 bit number. (For example: If I give it 010 it will give output 101.)

I used a 741LS138 3 to 8 decoder and an 8 to 3 encoder (the 8 to 3 encoder is working fine.)

The problem is that it does not show the desired output.

When I try to provide input the output always stays 0.

I have made a truth table. I cannot figure it out what is wrong with it.

The circuit that I made:

enter image description here

Truth table:

enter image description here

Here is the schematic of the 8 to 3 encoder which I built:

enter image description here

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    \$\begingroup\$ "Problem is it is not showing desired output." Well tell us what it is showing. That will be important information in debugging your problem. Edit it into your question. \$\endgroup\$
    – Transistor
    Commented Apr 1, 2021 at 20:07
  • \$\begingroup\$ electronics.stackexchange.com/search?q=3+to+8+decoder \$\endgroup\$
    – D.A.S.
    Commented Apr 1, 2021 at 20:44
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    \$\begingroup\$ Have you set E1 high and checked good connection to E2 as it is gray? \$\endgroup\$
    – Justme
    Commented Apr 1, 2021 at 21:44
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    \$\begingroup\$ "I am trying to build a circuit using only encoders and decoders" - but you're not using only encoders & decoders, you have a handful of inverters there too - which makes me wonder why bother with the encoders & decoders instead of just inverting the 3 bits ... ? \$\endgroup\$
    – brhans
    Commented Apr 2, 2021 at 1:58

1 Answer 1

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Thanks everyone

I finally figured it out. I have constructed 1 encoder and decoder then followed truth table. It works just fine.

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