I'm currently working on a phototransistor that is part of a reflective optical sensor. Now I saw a circuit, which looks like this and I'm wondering why there is the (additional) resistor \$R_3\$ ?
In my understanding the usual phototransistor circuit is a voltage divider between \$R_2\$ and the resistance of the transistor (i.e. low illumination \$\propto\$ high resistance and bright illumination \$\propto\$ low resistance). Then the analog output of the circuit will read a value between \$VCC\$ and almost zero (determined by the dark-current).
However, here I cannot explain to myself why we have the resistor \$R_{3}\$ in front of the analog out?
Thanks for your help!