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What are the pros and cons of using these different transducers?

I can't find see what the difference would be between either of them? I mean, they are all used in converting energy right?

  • Linear variable differential transformer (LVDT)
  • Variable-area capacitive transducer
  • Variable-separation capacitive transducer

Thanks guys

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  • \$\begingroup\$ Actually, none of those sensors convert energy; they must all be driven with a signal. \$\endgroup\$
    – Dave Tweed
    Jan 29, 2013 at 1:56

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LVDT's are very sensitive, but fairly expensive. They use mutual inductance to determine the position of a moving slug. You pass a sine wave through an input, and you measure the envelope of the sine wave out to determine displacement. the PHASE of the output sine wave determines whether you have a positive or negative displacement, so you need phase detection algorithms to provide an output, and the commercial processors tend to be pricey.

Capacitance is defined as \$ C = \frac{\varepsilon \varepsilon_0A}{d} \$, where A is Area of the overlap of the plates of the cap, and d is the distance between the plates. Thus, the output of a Variable Area device will be linear with area, which you can easily arrange to be linear with displacement. The output of a separation device is proportional to 1/d, which might be VERY sensitive, but it's not linear. You can probably build an amp that linearizes it without too much trouble, but, the world not being a perfect place, you'll likely lose sensitivity.

The circuitry to support either type of capacitive sensor is here. I lean toward some type of 555 timer arrangement as opposed to any type of AC bridge, which I find tricky.

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