Please excuse my schematic.
This is a tiny PCB near the DC5.5 Jack port of a laptop power supply. The transformer is broken so I dismantled it to learn some. The transformer reads like "220VAC to 19VDC 1.750A - 2.370A".
My question is : How do these 2 green LEDs light?
Both R1 and R2 read "75B", which according to the internet is 5900 Ohms, which is also what my multimeter reads (5.9K Ohms).
Correct me if I am wrong : the current that comes to the R1 branch is I = V/R = 19 / 5900 = 0.003 Amps (3 mA). Isn't this too low? LEDs are probably 02xx or 04xx (crazy tiny) by the way.
Now the voltage drop accross R1 would be : V = RI = 5900 * 0.003 = 17.7 V
Which means I have 2.3V left for LED1, which seems right actually! I checked with my bench PSU, the LED1 requires no less than 2.3V to light up (after removing desoldering it), but I do not have the greatest equipment to show exactly how much amps that LED1 draws (my PSU shows 0.000A)
R1 and R2 also are very tiny SMDs. How much power do they dissipate? I believeit is P = 0.003 * 17.7 = 0.051 Watts?
Can someone please correct me?