I've been trying to solve a book problem from Hayt, et al. Engineering Circuit Analysis (8th Ed.) —Practice Problem 11.9.
And here's my latest attempt, I just can't see what I'm doing wrong, why I don't get the answers from the book. Probably it's just some blunder I don't realize I'm making like a sign or a rule poorly applied. Please help me understand what I'm doing wrong.
\$V_1\$ is the voltage of the 1 \$\Omega\$ resistor.
The input impedance of the circuit is given by:
$$\underline{\text{Z}}_{\space\text{i}}=1+\left(\left(5+10\text{j}\right)\space\text{||}\space-10\text{j}\right)=21-10\text{j}\tag1$$
Where \$\alpha\space\text{||}\space\beta:=\frac{\alpha\beta}{\alpha+\beta}\$.
So, the input current is given by:
$$\underline{\text{I}}_{\space\text{i}}=\frac{\underline{\text{V}}_{\space\text{i}}}{\underline{\text{Z}}_{\space\text{i}}}=\frac{120\exp\left(0\text{j}\right)}{21-10\text{j}}=\frac{2520}{541}+\frac{1200\text{j}}{541}\tag2$$
So, we get:
$$\text{S}_{1\space\Omega}=\left|\frac{2520}{541}+\frac{1200\text{j}}{541}\right|\cdot\left|1\cdot\left(\frac{2520}{541}+\frac{1200\text{j}}{541}\right)\right|=\frac{14400}{541}\approx26.6174\space\text{VA}\tag3$$
