This Finder relay series specifies
Power lost to the environment
- without contact current 0.4 W
- with rated current 1.4 W
And a rated current of:
Rated current/Maximum peak current 10A / 15A
If I am getting everything right, this would translate to a contact resistance $$ R = \frac{P}{I^2} = \frac {1 {\rm\,W}} {{10}^2 {\rm\,A}} = 10 {\rm\,m\Omega} $$
I find it strange since other similar relays specify 100 mΩ for contact resistance, also made of AgSnO2. On the other hand, maybe they have an extra powerful spring / more material - This paper mentions:
With the SnO2 content increase from 15 wt.% to 30 wt.%, it was found that contact resistance of Ag–SnO2 materials increased by 33% and stabilize in 5 mΩ when contact force over than 70 N
Is there a mistake in my judgement / datasheet?
FWIW I am interested in the contact resistance when the coil is not energized.