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I have a question regarding a Li-ion charger/protector module. The board I'm using a fairly standard Li-ion charger/protector module. enter image description here

This module manages the charge using a TP4056 IC and has a built-in protection circuit using the DW01A IC.

Can I use this module safely to charge a 3.7 V Li-ion battery without internal protection? Most Li-ion batteries have an internal protection circuit (see image). enter image description here

But when I use the TP4056 module as described and a battery with internal protection there is a double protection, and this seems to be causing problems. So I want to use a battery without this internal protection. enter image description here

I'm assuming this is OK since the protection is present in the system only it is on the charge PCB and not on the battery. But I have done a lot of research and I'm still not a 100% sure so I was hoping someone could help here.

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It's OK to have two protector boards, one on the Li-ion battery and the other in the charging/protection module.

If necessary, one of the two protectors will turn off. It doesn't matter which because the result is the same: the LI-ion cell will be protected.

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    \$\begingroup\$ PS: The problem i have seems to be that same that is described in this post. The problem resolves when i test with the protection circuit removed from te battery. electronics.stackexchange.com/questions/588753/… \$\endgroup\$
    – Stijn
    Commented Nov 25, 2023 at 15:22
  • \$\begingroup\$ @Stijn Schreutelkamp " if there is a proper security circuit on the charge board then could I not just use a battery without protection?" You could use a "cell" without protection. Yes. \$\endgroup\$ Commented Nov 25, 2023 at 15:55
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    \$\begingroup\$ Again thank you very much! i will try to figure out best i can is the protection circuit on the charge board is safe. It seems i need to study more just to be safe. \$\endgroup\$
    – Stijn
    Commented Nov 25, 2023 at 16:37
  • \$\begingroup\$ "thank you very much". Please upvote and accept my answer. \$\endgroup\$ Commented Nov 25, 2023 at 17:51

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