0
\$\begingroup\$

Currently I am trying to self learn electronics. After the diode I moved to the transistor.

I understood the transistor as an “electronic” switch with no moving parts. When the base is connected, then the current can flow from the collector to the emitter. Otherwise it cannot.

Though, when I put 5v across the base, with no voltage across collector nor emitter, an LED, connected to the emitter through a resistor, lights up. Is this normal? Am I missing something on the functions of a transistor?

\$\endgroup\$
1
  • 1
    \$\begingroup\$ When the base is connected ... that is not entirely correct \$\endgroup\$
    – jsotola
    Commented Nov 29, 2023 at 22:29

3 Answers 3

1
\$\begingroup\$

Yes, it's normal, current into base flows out from emitter, regardless of what connections, if any, you have on the collector.

The base current controls the collector current. Both base and collector current come out of emitter.

\$\endgroup\$
1
\$\begingroup\$

schematic

simulate this circuit – Schematic created using CircuitLab

Figure 1.

  • (a) A transistor when tested with a diode tester appears to be a pair of PN (diode) junctions.
  • (b) In this case Q2 is being used as a diode and performs the same as D4 would in the equivelant circuit.
\$\endgroup\$
1
  • \$\begingroup\$ Transistor, Is it that hard to set some resistance values for the resistors to make the circuits come to life? \$\endgroup\$ Commented Nov 29, 2023 at 22:14
0
\$\begingroup\$

The base-emitter junction is a PN junction which is broadly similar to (but obviously with important differences from) a diode's PN junction that also allow it to control the flow of charge carriers to/from the collector. Like @justme mentioned, current into the base exits through the emitter just as if you had connected a diode. The transistor's base connection is, however, not designed to carry large currents like a diode, so be sure to limit the current with a resistor.

\$\endgroup\$
1
  • \$\begingroup\$ VIR, I think that under normal forward-voltage application, the base-emitter junction behaves exactly like a diode (the input source "sees" a diode). Perhaps the only difference is apparent when reverse voltage is applied; the junction breaks too early. \$\endgroup\$ Commented Nov 29, 2023 at 22:19

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.