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I have a small understanding of how to solve limits to infinity for regular rational equations, but I'm unsure of how to apply this to the Z-Transform initial value theorem.

The equation is: \$ \lim_{z \rightarrow \infty} \frac{10z^{-1}+5z^{-2}}{1-1.2z^{-1}+0.2z^{-2}} \$

The answer for this is that \$ x(n) = 0 \$, but I'm unsure of how to arrive at that.

I have watched this YouTube video which helps with understanding the general concept, but I'm not sure how to apply this to Z-Transforms.

Any help would be much appreciated.

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    \$\begingroup\$ It seems quite easy to me: all the terms with z have a negative exponential, therefore go to 0 when z goes to infinite. You remain with 0/1. \$\endgroup\$
    – clabacchio
    Commented Dec 1, 2013 at 0:53

1 Answer 1

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$$\lim_{z\to\infty}z^{-1} = 0,$$

so your limit becomes

$$ \frac{0 + 0}{1 - 0 + 0},$$ or \$\frac{0}{1}.\$

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