I want to reduce my apmlifier output to line-level. I found this tutorial which is compatible with 50Watts output power. There is also mentioned what to do if amplifier is more powerful than that. So if 10Kohm resistor handles 50Watts and 33Kohm handles ~300Watts, what is compatible with my amplifier which output power is 120Watts per line? Or can I just use the 33Kohm resistor?

  • \$\begingroup\$ 120W @ 4Ω ⇒ 22k; 120W @ 8Ω ⇒ 33k \$\endgroup\$ – jippie Feb 19 '14 at 18:48

Ultimately you want a voltage, so it will be easier to think in terms of the voltage out of your amp. You say your amp has "120 W" output. Presumably that is maximum into a 8 Ω load. Sqrt(120W x 8Ω) = 31 V, which is the maximum RMS voltage from your amplifier. You want to get that down to 1 V or so, so something like this would work:

However, that would require cranking your power amp to maximum gain to get the full line voltage signal. I'd probably attenuate by only half as much, which means making R1 1.5 kΩ or thereabouts. Whatever the line level signal is fed into isn't going to get hurt by 2 V instead of 1 V, just that it will be very loud and may get clipped. That would be a clue to turn down the volume going into the power amp.

Keep the power dissipation of R1 in mind. The voltages accross R1 and R2 will have a ratio of R1/R2. When 1 V is accross R2 in the example above, then 30 V will be accross R1. (30V)2/3kΩ = 300 mW, so a "1/4 W" resistor isn't enough.

  • \$\begingroup\$ Thanks! This looks so professional for me and is exactly what I needed! =) I will use 2Kohms for R1 to make sure that the sound will not get clipped \$\endgroup\$ – LizNet Feb 19 '14 at 19:59
  • \$\begingroup\$ Should I use 8 Ohm resistor or something to make load to the amplifier? \$\endgroup\$ – LizNet Feb 19 '14 at 20:04
  • \$\begingroup\$ @nTn: That depends on your amp. Some amps are OK with no load, some not. It should work in all cases with a 8 Ohm load, since that's what a ordinary speaker is. However, it will dissipate significant power and require a physically large resistor, so it's not something I'd do unless I found it was really necessary. \$\endgroup\$ – Olin Lathrop Feb 19 '14 at 20:15
  • \$\begingroup\$ If I don't use load resistor, can that circuit be used parallel with speaker on both lines (left and right)? \$\endgroup\$ – LizNet Feb 19 '14 at 20:16
  • \$\begingroup\$ @nTn: Yes, you need one of these for each separate speaker signal (left and right). A speaker would work as a load for your amp, but of course it will make sound in the process. \$\endgroup\$ – Olin Lathrop Feb 19 '14 at 20:19

According to the rule of thumb on the page you refer to:

  • 120W @ 4Ω ⇒ 22k or
  • 120W @ 8Ω ⇒ 33k.

But essentially you want to check the output voltage of the amplifier and you want to reduce that to 1Veff. Use the voltage divider rule for that.

Not all amplifiers like unloaded outputs. Does your amp have a headphones output, that would be a much safer option to experiment with. You don't want to accidentally sort normal output of your amp.

  • \$\begingroup\$ I have headphones output, but it switches off speakers output =/ \$\endgroup\$ – LizNet Feb 19 '14 at 19:56

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