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I was about to wire my guitar using this official scheme duncan and I can't seem to understand it properly. I get that the signal is going through the black wire to the volume pot, but how does it get (and more importantly - return modified) to the tone one (lower on the pic)? I supposed there should be a circuit for the signal to go there and then return, but there's one wire connecting the pots and that's it, the other one is just ground.

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    \$\begingroup\$ Have you tried drawing out the schematic yet? \$\endgroup\$ – Ignacio Vazquez-Abrams Feb 21 '14 at 9:00
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Black is the hot wire from the pick up and it goes to two places; the volume pot and the tone pot. The volume pot ratios the hot wire and feeds it to the output jack. Note the green wire - it should be regarded as ground and it connects to both pot bodies and ground on the jack socket. Note also the cold end of the volume pot also connects to green via its body.

The tone control pot via a small capacitor shunts high frequencies from hot to ground. If the pot is turned one way it hardly has any effect.

enter image description here

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  • \$\begingroup\$ Thanks for explanation, but the tone pot still looks like a dead end with just one wire connecting it with another pot. If it helps anyhow: I would've had no questions if the jack was wired to the tone's output. \$\endgroup\$ – Atas Feb 21 '14 at 9:56
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    \$\begingroup\$ The tone pot controls how much the cap can short-circuit the output to ground. There are two wires that pot: ground and signal. A capacitor will look like a short-circuit to high(er) frequencies. Frankly, it's a really cheap & nasty way to do tone control, but artists aren't engineers so no-one grumbles, or they just use bullshit terms like saying it adds character or colour or whatever. \$\endgroup\$ – John U Feb 21 '14 at 10:10
  • \$\begingroup\$ @Atas picture added \$\endgroup\$ – Andy aka Feb 21 '14 at 10:53

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