1. What is the definition of apparent power?
  2. How to calculate apparent power for three-phase circuit? Is it S = S1 + S2 + S3 or S = sqrt(P^2 + Q^2)


    P is total active power P = P1 + P2 + P3


    Q is total reactive power in system Q = Q1 + Q2 + Q3?


Apparent power is the vector sum of real power and reactive power. In effect it is V\$_{RMS} \times I_{RMS}\$ without any consideration of phase angle. Because real and reactive power are at right angles, the vector sum is: -

\$\sqrt{Real^2 + Reactive^2}\$

Once you have it for one phase then it you can, just like in real power) multiply by 3 to get the value for a balanced supply/load 3-phase system.

|improve this answer|||||
  • \$\begingroup\$ In fact some measurement devices calculate aggregate as arithmetic sum, some as vectorial sum (like for example meters from "Meter Test Equipment" www.mte.ch company). Is somewhere authoritative source for this like for example IEEE commitee or ISO norm? \$\endgroup\$ – truthseeker Feb 28 '14 at 11:41
  • \$\begingroup\$ @truthseeker when it comes to powers (real, apparent or reactive), in a 3-phase circuit they should be simply additions of quantities - they are not meaningful vector quantities when comparing between phases. Anyway, I don't know of any authoritative source other than what I was force-fed at college many years ago!! \$\endgroup\$ – Andy aka Feb 28 '14 at 11:54

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.