Unfortunately, you will have to accept losses in your signal if you try to reconstruct them from the samples. Unless you make certain strong assumptions about the audio signal the Nyquist-Shannon sampling theorem doesn't help. A general raw audio signal will not satisfy these conditions.
If you take \$K\$ samples at a rate of \$\frac{1}{2B}\$ starting at \$1/2B\$ where \$B\$ is the bandwidth then the functions
$$ \frac{\sin(2\pi t B)}{2 t B}$$
and
$$ \frac{\sin(2\pi t B - 2(K+1) \pi)}{2 t B - 2(K+1)}$$
are indistinguishable from each other using only the samples taken at times \$\frac{1}{2B}, \frac{2}{2B},...,\frac{K}{2B}\$ as both functions evaluate to zero at these points. The exact reproduction of a signal from Nyquist-Shannon sampling theorem assumes an infinite number of sample points.
Things get slightly worse once FFT is involved. FFT reproduces the signal as a finite sum by using a finite set of frequencies determined by your sampling rate. If you have a raw audio signal, you have an possibly infinite set of frequencies being received despite being limited by \$B\$.
In more mathematically correct language the space of functions with bandwidth \$\leq B\$ is a infinite dimensional vector space. Once you fix a sampling rate the vector space of functions constructed via FFT is finite dimensional and thus not all signals can be recovered exactly via FFT.