# Internal resistance of Function Generator

I'm using a function generator that has a 50ohm internal resistance. Does this affect any circuit that I may connect it to and if so, how would it affect the results?

• The output of the function generator with internal resistance [R] will drop its output voltage by [D] according to how much current [I] your circuit draws from it, according to ohm's law: [D = IR]. Apr 30 '14 at 3:03
• This might be helpful, I suspect. Why your function generator outputs twice the programmed voltage Apr 30 '14 at 3:35

For example, for a 5 Volt signal output setting, and using a matched 50 Ohm load for X above, the current through the loop will be: I = V / R = 5 / 100 = 50 mA. This is the nominal, specified case. As load 'X' is changed, the current drawn will change, and thus the voltage across the load changes correspondingly.