I am given a balanced 3 phase circuit question shown in the linked image. I am confused on the difference between apparent, average and reactive power and how each is calculated. This is my first post so I hope it is in accordance with the rules. Thanks
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1\$\begingroup\$ Do you know how to calculate a single phase circuit? If you do then you know how ro calculate this. Try superposition, it will help you with your understanding of 3ph systems. You will see that it is not that hard! \$\endgroup\$– WalyKuMay 8, 2014 at 13:40
1 Answer
I am confused on the difference between apparent, average and reactive power and how each is calculated
Average power is the real power you get billed for as kWh and, is the numerical multiplication of voltage and current waveforms, often done in an MCU these days but back in the old days a thing called a wattmeter did things magnetically then, along came analogue multiplier chips and solid state magnetic multipliers as patented by Landis & Gyr. This is all about four quadrant multiplication of the instantaneous signals and not to be confused with either of the following: -
Apparent power is RMS voltage x RMS current and only equals average power (above) on a purely resistive load. For pure sinewaves: -
\$Power_{Average} = Power_{Apparent}\cdot Power\space Factor\$
i.e. \$P=V\cdot I\cdot Cos{\phi}\$
Where power factor is the cosine of the phase angle between voltage and current - clearly when that angle is zero, power factor = 1.
Reactive power is \$\sqrt{Apparent^2 - Average^2}\$: -
See also this site for further details.