Here is the schematic:
I got a little problem in electronics: it involves simple things but I can't figure it out (and found no other circuit that was the same configuration).
At t < 0 ms
, both switches are open.
The problem is the following : when t = 0 ms
, the switch I is closed and the switch II is open. Then I need to make an equivalent circuit when one DC source is in series with A and B (from UAB = UTH), to find the value V0 and calculate the exponential equation for the voltage of the capacitor.
Do we remove the branch that is open to calculate UTH or do we keep it? In short, is Uth (when t = 0ms
) equal to 0V or 10V?
The question is here: if we close the switch I, and if V1 is equal to 10V, the equation for the capacitor being equal to \$V_1 + (V_0 - V_1) \times e^{(-t/TAU)}\$ will be equal to 10V constant, which doesn't seem logical since we added one resistance in the circuit!
But if V1 is equal to 0V, it would not be logical since the capacitor is in series with the 10V DC...
Can you please guide me in the right direction or tell me what I did wrong?