I've come across an interesting transimpedance amplifier toplogy, that reportedly reduces voltage and current noise and compensates for large photodiode capacitance. However, as I'm working with an avalanche photdiode, and I need to bias it with at least 65V - how exactly would I be able to adapt the circuit for such high voltages?
Your source, of course, is http://www.electrooptical.net/www/frontends/frontends.pdf.
A direct adaptation is fairly simple. Rbias should be connected to -15, as shown, but the 20K resistor must be tied to a separate bias voltage, Vb. For a given diode bias voltage Vd, Vb = 1.67 Vd. In your case, this would call for a Vb of about -100 volts.
All of this supposes that you need the performance. Do you? What photodiode current level are you expecting? What is the photodiode capacitance when biased? How much bandwidth do you need? What SNR do you need? Go back to the article. Start with your expected current level and desired output voltage. This determines the value of the transimpedance amplifier resistance. Now use this, along with the diode capacitance and the input capacitance of your op amp, to model a simple TIA with a small feedback amplifier. Calculate the bandwidth. Is this adequate? If so, go no farther. There is an old saying: those who ask for more bandwidth than they need get what they deserve.