So I have been looking at building a circuit for a water-powered motor that I have been trying to develop.
After that, I need to do something in particular with it, I need the output to look sort of like AC in the sense that the current switches directions. Let me explain the purpose and the planned additions that I will need to make it happen.
I am trying a concept of a water cell where the water serves essentially as a dielectric in a capacitor. Don't worry about why or how, what makes it happen, but take for granted that I will need relatively high frequency and high voltage AC going through there, or DC pulsed. Now, the point is not to break down the water at this stage, so what I want is simply high voltage positive and negative pulses on the two plates of the "water capacitor" going back and forth as in AC current. I said that the point is not to break down the water, at least not at this stage: that means that current will not "break-through" the dielectric, but the pulses of the electric field, in the form of the potential, or high voltage will constantly change the electric charge of the plates (of the "water capacitor").
So, the high voltage transformer was made to make arcs, and as such does not allow output shorting or a no-load situation. I want that transformer to connect to the water capacitor. Now, a capacitor is a load, but not always, if I understand correctly, and I don't want the pressure to destroy the transformer. As such, right after the transformer before the water capacitor, I was considering adding this resistor
Well, I did some calculations on what the transformer might draw, and I will be using at max 18 watts of power, it just depends on what the high voltage transformer draws.
3V : 6 Watts : 2 Amps
4V : 8 Watts : 2 Amps
3V : 13.5 Watts : 4.5 Amps
4V : 18 Watts : 4.5 Amps
As such, I wanted to have a load present so that undue stress was not put on the high voltage transformer, causing it to no longer function properly, if at all. That load would be the resistor. I did a little extra so that it didn't burn up, and I allowed for the Ohms not to be too high, because I want the high voltage present for the pulses.
Now, there are a few things that bother me about the circuit so far. The high voltage transformer works sort of like an ignition coil from what I understand, but it builds up voltage until it can arc, and does arc. So I feel like that is a steady build-up, and that is ok, and it is not supposed to short to the input of the circuit, so that is even better, however, how would I get that switch of direction present in AC with the present set-up?
Battery(4V 4.5Ah)----[DC, constant flow of this]
High Voltage Generator(20kV 0.9mA (max))----[quick constant electric pressure as output]
Resistor(25Ω 20W)----[max 112.5V loss, still at least 19kV for sure even with other losses]
Water Capacitor(charging, uncharging cycle for each plate, but no breakdown)
That is it for the set-up. If anyone has improvements that they would like to suggest on my design so far or errors to point out (but please read until the end before you do), feel free to, as well as if anyone can find a high voltage transformer that can get like 3V with no minimum wattage and just milliamps to at least 20kV, that would be great. However, my real questions come now.
If you noticed, the high voltage transformer in the current set-up charges, but has no way of releasing as the water capacitor doesn't have a point where current flows through it, only the pressure build-up. So, I was thinking of a switch before the transformer, looking into different kinds, probably a transistor, because of the wear and speed and automatic factors in consideration. Problem: I don't have any idea how to make one work with a battery and need an automatic switch, preferably not using up a lot of power or requiring a ton of parts. I need help with this.
Also, to go with the switch, I was considering hooking up a normal capacitor after the water capacitor to gain power and, when the switch turns the transformer off, to allow for the flow of electricity to power the other plate of the water capacitor, switching the charge, and create the AC like effect. I have no idea if or how that would work. My thought process is that it will probably charge the second capacitor as well, because it won't be able to get anywhere with the first one. However, how would it charge the second capacitor and if it does, would it be charged with a high voltage low amperage combination or change things a bit to deal with it? Also, I was kind of wondering about the flyback voltage from the second capacitor discharge, and if I would need anything to stop it, outside of the first capacitor, which should absorb it, as the current has switched directions from the perspective of the water capacitor, and the resistor.
As such, this is my current picture of the circuit.
So, as you can see, I have a problem with the switch and with the secondary effect which is so crucial to creating a certain environment inside the water capacitor. Thank you for any help that anyone here can give. I still have much to learn, so please point out any mistakes and I welcome any safety concerns or tips that you might have to give. As I said, I have much to learn and am glad to learn it. Thank you again. I hope you all have a good day.