I have a Rigol DS1052E oscilloscope and a Rigol DG1022 function generator. I have just changed the oscilloscope fan for a silent one, as I found, as is commonly reported, that the original fan noise was very irritating. That seems successful and is the only modification I have made to the oscilloscope.

Testing the oscilloscope as a check, I connected the signal generator to it with a plain BNC cable (both ends BNC), and set the signal generator to a 5 volt peak-to+peak 1 kHz sine wave, and the voltage was confirmed by a digital voltmeter showing 3.67 or so V RMS. However, the oscilloscope shows 10 V p/p, and this also happens for a 100 kHz sine wave. Testing other amplitudes, it is not always precisely two to one, but it is round about that ratio.

Why does the oscilloscope show twice the voltage as the signal generator? I hope it is something trivial that I have overlooked, and desperately not an "undocumented hardware modification", as we used to say in the lab when we dropped something and it no longer worked.

Well I need not have panicked. @Sephro has the solution. Thank you to him especially, and to the others for the helpful comments. I would have also accepted @alex forencich's version if I was allowed to. I was beginning to approach that answer myself, since I discovered that inserting a 50 ohm parallel load on the output of the sig. gen. cured the problem, I have done as @Seph suggested and set the sig. gen. output to "High Z" and that, too, makes the voltages shown coincide.

So, my extended explanation, from the answers given, is:

I see now that, to generate 5 V across a 50 ohm load, with its internal resistance also 50 ohms, the sig. gen. actually generates 10 V of which, because the two 50 ohms in series act as a voltage divider, only 5 V appears at the output terminals, and that is the value that is displayed on the sig. gen. panel. If a high impedance load such as an oscilloscope is attached, then the voltage divider is distorted, with a very small drop across the sig. gen.'s internal 50 ohms, and very nearly all across the 'scope input. The sig. gen. does not "know" this and still gives the same display as for the 50 ohm load. As @Seph says, there is a "High Z" setting for the DG1022 sig. gen. that (in effect?) replaces the internal impedance with a high impedance to match the load, so the voltage divider effect is restored.

  • \$\begingroup\$ Are you totally positive that the old behaviour was as you expect it to be now? \$\endgroup\$ Commented Jul 4, 2014 at 19:16
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    \$\begingroup\$ 3.6Vrms = 5V peak(approx) = 10V pk-pk. \$\endgroup\$
    – user16324
    Commented Jul 4, 2014 at 20:12
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    \$\begingroup\$ @BrianDrummond Bingo. There is no problem here. \$\endgroup\$
    – Kaz
    Commented Jul 4, 2014 at 23:05
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    \$\begingroup\$ Right, the remaining question is why the sig gen reads differently, and I suspect Spehro's answer nailed that. \$\endgroup\$
    – user16324
    Commented Jul 5, 2014 at 9:48
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    \$\begingroup\$ No, High Z describes the load the generator needs to drive, not the source impedance. \$\endgroup\$ Commented Jul 5, 2014 at 12:45

3 Answers 3


The DG1022 signal generator has an output impedance setting- High Z and 50\$\Omega\$ (or some other resistance).

If you set it for 50\$\Omega\$ then you need to terminate it with 50\$\Omega\$ or you'll get double the output voltage!

enter image description here

Set it to High Z and all will likely be well.


Generally the voltage setting on generators is half of what the open circuit output voltage is, though it depends on the generator. Usually signal generators are designed to drive a 50 ohm load, so they have a 50 ohm source impedance for matching purposes. As a result, the voltage across the load will be proportional to the load impedance. If the generator puts out 1 volt at no load, then you will get 0.5V across a 50 ohm load (the 50 ohm source and load impedances act like a voltage divider). The output voltage setting compensates for this. Try setting your scope input to 50 ohms, if it supports this. If not, connect them both to a 50 ohm resistor. It may also be possible to disable the 50 ohm load impedance compensation in the generator.

By the way, the peak-to-peak voltage will be about 2.8 times the RMS voltage, so 3.276 x 2.8 = 10.276. So the scope is showing the correct voltage, it's just not the voltage you were expecting.

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    \$\begingroup\$ Although Spehro's accepted has the right solution for the OP's specific equipment, I think this is actually a more informative answer for the general question and explains the difference between the normal and the High-Z mode suggestion there. \$\endgroup\$
    – natevw
    Commented May 15, 2015 at 17:23

The proper way to calibrate the probe and scope is with a square wave as provided in the lower right corner.

This way frequency response and DC gain are both checked.

To calibrate probes, read manual for auto-compensation. To calibrate gain, read the autocal section of manual.

Disconnect any probes or cables from all channel inputs, otherwise failure or damage to the oscilloscope may occur. Press →Self-Cal to enter the self-calibration interface as follows. Press “RUN/STOP” key to start the operation and press “AUTO” key to exit the system

If the generator gives the same result with a 50 Ohm load, consult factory.

With high impedance load, expect result to be 2x selected output. Output drops 50% with a matched load.


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