# how can i calculate if my motor can drive me uphill? [closed]

Well i'm building something on my free time and I want to buy an engine and I would like to know if it is strong enough to carry me uphill. Is there a formula i can use?

This is what is know to me (added an engine i have my eyes on): Engine (hub engine would be inside wheel): Volts - 36v Watts - 361w Torque - 22.83 N.m RPM - 151 n

body: Wheel radius - 15.3 cm Body weight (with batteries, chassis, my weight and motor weight included) - 75 kg

Transmission: Hub engine - not transmission. the engine itself spins and is located at the center of the wheel (i think this means that the differential is 1). environment: expected to go ~35 degrees uphill

At what speed am i expected to go uphill? At what acceleration? How do i calculate this?

Further more, i found lots of engines that only state watt, RPM and volt. is this enough to calculate torque?

thank you very much in advance!

## closed as unclear what you're asking by Chetan Bhargava, Daniel Grillo, Leon Heller, Matt Young, Olin LathropJul 6 '14 at 22:20

Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.

• I'd say this was more physics than electronics... – Majenko Jul 6 '14 at 18:04
• Ben, please use proper English capitalization. – Nick Alexeev Jul 6 '14 at 18:32
• Any motor can carry you uphill, in theory, if geared down far enough. – Spehro Pefhany Jul 6 '14 at 21:27
• @Nick: Yup. After reading the title and the first line, I had enough of the OP thumbing his nose at us. Downvoting, closing, and moving on. – Olin Lathrop Jul 6 '14 at 22:20

You haven't said anything about gearing so I'll assume direct drive.

Force = 22 Nm / radius 0.153m = 143N.