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Do there exist a solid state design circuit to do the following:

Charge multiple capacitors in parallel for a certain amount of time from a low voltage DC source, then disconnect them completely from the DC source and rearrange them in series to allow them to be discharged in series?

What I want is to charge about 10 capacitors in parallel with 12 V, then discharge them at 120 V in pulses.

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  • \$\begingroup\$ That is I believe basically how a "switched capacitor voltage doubler" works. I haven't seen one that deals with that kind of high voltage though, only like 2x5v=10v etc. You could do it with BJTs or MOSFETs I would imagine... \$\endgroup\$
    – Majenko
    Commented Jul 23, 2014 at 20:29
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    \$\begingroup\$ How much current when charging/discharging? \$\endgroup\$
    – tcrosley
    Commented Jul 23, 2014 at 20:50
  • \$\begingroup\$ Can you use a bank of form C (MAKE_BREAK_MAKE) relays to do the bouncy grunt work and then use a single transistor or mercury wetted relay to generate a nice pulse? \$\endgroup\$
    – EM Fields
    Commented Jul 23, 2014 at 21:38
  • \$\begingroup\$ It sounds like you're looking for the low-voltage, solid-state equivalent of a Marx generator. I suppose you could use diacs instead of spark gaps. Use an SCR in the first position to trigger the discharge. \$\endgroup\$
    – Dave Tweed
    Commented Jul 23, 2014 at 22:19
  • \$\begingroup\$ How about mechanical relays? (I know not solid state.) The problem with SS is some part of it has to be up at ~120V \$\endgroup\$ Commented Jul 23, 2014 at 23:58

3 Answers 3

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I think this is how you could do it in relays: -

schematic

simulate this circuit – Schematic created using CircuitLab

All the switches operate together so if you could use MOSFET SSRs I guess you'd be just about there. 2 Single SSRs can be made to form a c/o contact and you'll therefore need four per capacitor. Or just use relays.

R1 is the discharge load (whatever it may be) and you can step and repeat for as many capacitors as you wish but watch the relay contact open-circuit voltage ratings. A simpler version is this (I believe): -

enter image description here

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    \$\begingroup\$ in your second circuit, aren't we shorting C2 and C3 by creating a direct path back to source going from D4 to D1 and from D5 to D2 ? \$\endgroup\$
    – Lexos69
    Commented Oct 28 at 17:33
  • \$\begingroup\$ @Lexos69 yes, the final circuit is a bit of a mess and does not work so I shall delete that attempt using diodes. \$\endgroup\$
    – Andy aka
    Commented Oct 28 at 17:50
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Sounds like a charge pump, a voltage multiplier, a Cockcroft-Walton generator.

I often use a MAX232 level shifter ( Wikipedia: MAX232 ). While the charge pump in particular chip is designed to converts 5 V to +-10V, perhaps you might find useful the app notes Maxim and other have published explaining how charge pumps work. a b

The theory applies to any voltage. Specific implementations are generally designed for one particular output voltage. The MAX232 is designed to convert +5V to +-10V. Some Cockcroft-Walton generators are designed to generate millions of volts.

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  • \$\begingroup\$ No need for fancy switches; diodes can keep all the electrons in a row. \$\endgroup\$ Commented Jul 24, 2014 at 0:41
  • \$\begingroup\$ Yes, you could use the Cockroft-Walton circuit and drive it from an H bridge. \$\endgroup\$
    – user23614
    Commented Jul 24, 2014 at 10:01
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I am not sure what your application is but I think using am inductive boost would be less complicated and require fewer components. You would need an Input Cap, Output Cap, inductor and control circuitry (one FET, a diode and a controller). TI would probably have the controller. What you need to know is the output current and how much voltage ripple is acceptable.

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