In a practice test we are asked to find the Thevenin equivalent by finding the Thevenin voltage and Norton current within the following circuit.

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We were given the following answer for Vth:

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I feel like I'm making a simple mistake but I'm coming up with Vth= enter image description here which is equal to enter image description here as I see he wrote down. So why does it wind up as 7+7j?


Looks like you are both correct, although you are more precise. The "7's" in the result 7 + 7j are an approximation of 5*sqrt(2) which somewhat more precisely = 7.07107, so I would prefer the solution given in rectangular form be 7.1 + 7.1j since 7.07.... rounds closer to 7.1 than 7.0

  • \$\begingroup\$ Okay thank you. Makes sense, it was just slightly confusing. Maybe I needed some extra sleep! haha \$\endgroup\$ Aug 7 '14 at 3:58
  • \$\begingroup\$ Sometimes professors will drive you nuts by insisting on perfect precision from their students, then they go ahead and use approximations without warning you. [I know I've been fooled like that back in the day.] This may be one of those cases. Anyway, glad I could help. Would you kindly give me an up-vote on the answer provided ? I am new to this board and I could use the points. Thanks ! \$\endgroup\$ Aug 8 '14 at 21:00

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