I just bought some NPN transistors for my project. I didn't notice before buying them, that the specification said the transistor had a emitter base voltage \$V_{be}\$ of 9 volts. Can this be true? This value is normally 0.7 Volts right?

Here are a screenshot of the specifications:

enter image description here

  • \$\begingroup\$ What SP said - but note this is not a value you would usually get near in most circuits - it's just a limit. \$\endgroup\$
    – Russell McMahon
    Commented Aug 17, 2014 at 13:46

1 Answer 1


You're thinking of the base-emitter voltage (forward biased). The datasheet specification is for the emitter-base voltage, which is the reverse breakdown voltage (guaranteed minimum) of the emitter-base junction.

Most BJTs have a rating in the 5-9V range, a few have breakdown voltages similar to the collector-base breakdown voltage.


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